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9514 1404 393
Answer:
(x, y) = (2, -6)
Step-by-step explanation:
Subtract the first equation from the second.
(8x -2y) -(5x -2y) = (28) -(22)
3x = 6
x = 2
Substitute this into either equation and solve for y.
8(2) -2y = 28
8 -y = 14 . . . . . . . . divide by 2
y = 8 -14 = -6 . . . . add y-14 to both sides
The solution is (x, y) = (2, -6).
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I like a graphing calculator for a quick solution to such problems.
Answer:
x^2/25 +y^2/9 = 1
Step-by-step explanation:
You can think of an ellipse as a circle with a different scale factor in the x-direction than in the y-direction. When either dimension is stretched by a factor of k, the corresponding variable (v) is replaced by (v/k).
Here, the unit circle
x^2 +y^2 = 1
is stretched by a factor of 3 vertically (in the y-direction) and a factor of 5 horizontally (in the x-direction). That means we can replace x with (x/5) and y with (y/3) in the above equation to get ...
(x/5)^2 +(y/3)^2 = 1
Traditionally, the denominator is written as a number, not a square, so the equation would be ...
x^2/25 +y^2/9 = 1
