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3 years ago

Help with this question please?

Mathematics

1 answer:

tatuchka [14]3 years ago

4 0

Answer:

x^2/25 +y^2/9 = 1

Step-by-step explanation:

You can think of an ellipse as a circle with a different scale factor in the x-direction than in the y-direction. When either dimension is stretched by a factor of k, the corresponding variable (v) is replaced by (v/k).

Here, the unit circle

x^2 +y^2 = 1

is stretched by a factor of 3 vertically (in the y-direction) and a factor of 5 horizontally (in the x-direction). That means we can replace x with (x/5) and y with (y/3) in the above equation to get ...

(x/5)^2 +(y/3)^2 = 1

Traditionally, the denominator is written as a number, not a square, so the equation would be ...

x^2/25 +y^2/9 = 1

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How do you work out the rate, time and principal from the compound interest formula?

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Answer:

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Part 2) $r=n[\frac{A}{P}^{1/(nt)}-1]$ (see the explanation)

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Step-by-step explanation:

we know that

The compound interest formula is equal to

$A=P(1+\frac{r}{n})^{nt}$

where

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Part 1) Find the Principal P

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Divide both side by $(1+\frac{r}{n})^{nt}$

$P=A/(1+\frac{r}{n})^{nt}$

Part 2) Find the rate r

The values of A,P,n and t are given

Isolate the variable r

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Divide both sides by P

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Elevated both sides to 1/(nt)

$\frac{A}{P}^{1/(nt)} =(1+\frac{r}{n})$

subtract 1 both sides

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Part 3) Find the time t

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Isolate the variable t

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Divide both sides by P

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Apply log both sides

$log(\frac{A}{P})=log(1+\frac{r}{n})^{nt}$

Apply property of exponents

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Divide both side by $(n)log(1+\frac{r}{n})$

$t=log(\frac{A}{P})/[(n)log(1+\frac{r}{n})]$

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3 years ago

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Answer:

Step-by-step explanation:

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Hopes this helps:

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2 years ago