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Bogdan [553]
3 years ago
10

-1/4 (d + 1) < 2 solve the inequality

Mathematics
2 answers:
nevsk [136]3 years ago
7 0

Answer:

d>-4

Step-by-step explanation:

Illusion [34]3 years ago
3 0

Answer:

d > − 9?

Step-by-step explanation:

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How many trips can a truck with a 1 by 2 meter cylindrical tank take to fill a 890,000 liters tank?
Reil [10]
Tank diameter = 1m
radius = 0.5m
height = 2m
Volume of tank of truck = πr²h = 3.142 * 0.5² * 2 = 1.571m³ = 1571 litre

Volume of tank to be filled = 890,000 litre

no. of trips = 890000/1571 = 566.52 ≈ 567 trips
 

4 0
2 years ago
PLS ANSWER ASAP ILL GIVE U BRAINLIEST<br><br> f(x) = 2x^2 + 8x + 5<br><br> Find the range
Lady_Fox [76]

Answer:

v min (-2;-3)

Step-by-step explanation:

its going to be a parabola with a minimum of (-2;-3) I hope it helps

5 0
3 years ago
Ruby uses 7.2 pints of blue paint and white paint to paint her bedroom walls. 3/4 of this amount is blue paint, and the rest is
Nuetrik [128]

Answer:

1 4/5 or 1.8 pints are white

Step-by-step explanation:

1/4 of 7 1/5 = 1/4 x 36/5 = 36/20 or 9/5, which is 1 4/5

5 0
3 years ago
What is the answer please.... need help
mina [271]

Answer:

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Step-by-step explanation:

Given the function

f\left(x\right)=x^3-6x^2+3x+10

As the highest power of the x-variable is 3 with the leading coefficients of 1.

  • So, it is clear that the polynomial function of the least degree has the real coefficients and the leading coefficients of 1.

solving to get the zeros

f\left(x\right)=x^3-6x^2+3x+10

0=x^3-6x^2+3x+10              ∵  f(x)=0

as

Factor\:x^3-6x^2+3x+10\::\:\left(x+1\right)\left(x-2\right)\left(x-5\right)=0

so

\left(x+1\right)\left(x-2\right)\left(x-5\right)=0    

Using the zero factor principle

if  ab=0\:\mathrm{then}\:a=0\:\mathrm{or}\:b=0\:\left(\mathrm{or\:both}\:a=0\:\mathrm{and}\:b=0\right)

x+1=0\quad \mathrm{or}\quad \:x-2=0\quad \mathrm{or}\quad \:x-5=0

x=-1,\:x=2,\:x=5

Therefore, the zeros of the function are:

x=-1,\:x=2,\:x=5

f\left(x\right)=x^3-6x^2+3x+10 is the function of the least degree has the real coefficients and the leading coefficients of 1 and with the zeros -1, 5, and 2.

Therefore, the last option is true.    

8 0
2 years ago
The circle below is centered at the point (4,3) and has a radius length 5. What is its equation
Crazy boy [7]
The equation of a circle centred at point (m,n) and radius r is given by

<span>(x-m)² + (y-n)² = r²
</span>-------------------------------------------------------------
Centre = (4,3)
radius = 5

Equation:
(x - 4)² + (y - 3)² = 5²
⇒ x² - 8x + 16 + y² - 6y + 9 = 25
⇒ x² + y² - 8x - 6y + 25 = 25
⇒ x² + y² - 8x - 6y = 0

The equation of the circle is x² + y² - 8x - 6y = 0

Hope it helps!
3 0
3 years ago
Read 2 more answers
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