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Mekhanik [1.2K]
3 years ago
7

A DVD player with a list price of $100 is marked down 30%. If John gets an employee discount of 20% off the sale price, how much

does John pay for the DVD player ?
A. $86.00
B. $77.60
C. $56.00
D. $50.00
E. $44.00
Mathematics
2 answers:
77julia77 [94]3 years ago
7 0
30% = 0.30
100 - 100(0.30) = 70

20% = 0.20
70 - 70(0.20) = 56

the answer is c
kykrilka [37]3 years ago
4 0

Answer:

C. $56

Step-by-step explanation:

We have been given that a DVD player with a list price of $100 is marked down 30%.

Let us find the price of DVD player after marked down by figuring out 70% (100-30) of $100.

\text{Price of DVD player after marking down}=\frac{70}{100}\times \$100

\text{Price of DVD player after marking down}=\$70

Therefore, the price of DVD player after marking down by 30% will be $70.

As John gets an employee discount of 20% off the sale price, so to find the amount paid by John we need to figure out 80% (100%-20%) of $70.

\text{The amount paid by John for DVD player}=\frac{80}{100}\times \$70

\text{The amount paid by John for DVD player}=8\times \$7

\text{The amount paid by John for DVD player}=\$56

Therefore, John paid $56 for the DVD player and option C is the correct choice.

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Answer:

95%

Step-by-step explanation:

The Empirical rule, also the 68–95–99.7 rule, states that for a population that is approximately normal or symmetrical, nearly all of the data values will lie within three standard deviations of the mean;

68% of data values will fall within one standard deviation from the mean

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From the graph given, we note that the weights 60 and 80 pounds fall within two standard deviations from the mean;

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<h3>¿Cómo calcular el esfuerzo aplicado sobre el cable?</h3>

La caja tiene masa y está sometida a un campo gravitacional, por tanto, tiene un peso (W), en newtons. Por el principio de acción y reacción (tercera ley de Newton), encontramos que el cable es tensionado debido a ese peso y su área transversal experimenta un esfuerzo axial (σ), en pascales.

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La falta de problemas verificados en español sobre esfuerzos axiales obliga a buscar uno equivalente en inglés.

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