I took the liberty of finding for the complete question.
And here I believe that the problem asks for the half life of Curium. Assuming
that the radioactive decay of Curium is of 1st order, therefore the
rate equation is in the form of:
A = Ao e^(-kt)
where,
A = amount after t years = 2755
Ao = initial amount = 3312
k = rate constant
t = number of years passed = 6
Therefore the rate constant is:
2755/3312 = e^(-6k)
-6k = ln (2755/3312)
k = 0.0307/yr
The half life, t’, can be calculated using the formula:
t’ = ln 2 / k
Substituting the value of k:
t’ = ln 2 / 0.0307
t’ = 22.586 years
or
t’ = 22.6 years
Answer:
9/16 or 0.5625
Step-by-step explanation:
Answer: 5%
Step-by-step explanation:
To find the sales tax, find the difference between before and after tax:
0.63 - 0.60 = 0.03
To find the percentage, divide the difference by the cost of the product:
0.03/0.60 = 0.05
Multiply by 100 to find percent sales tax:
0.05 x 100 = 5%
Answer:
a finite combination of symbols that is well-formed according to rules that depend on the context
Step-by-step explanation:
why do i feel like you have the same math teacher as me he asked me the same question on google classroom anyways hope this helps
Answer:
0.9
90%
Step-by-step explanation:
Dividing 10 into 9.0 we get the decimal 0.900.
As a percentage this is 0.900 * 100 = 90%
