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3 years ago

5

Convert tge following fraction to decimal and then to percent. Round the decimal to three places before converting to percent 9/

10

1 answer:

katen-ka-za [31]3 years ago

5 0

Answer:

0.9

90%

Step-by-step explanation:

Dividing 10 into 9.0 we get the decimal 0.900.

As a percentage this is 0.900 * 100 = 90%

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A shop sold small and large tin fish in the ratio 2:3 if 600 small tinned fish sold how many large tinned fish were sold??and fi

Dafna1 [17]

Answer:

900 Large Fish

1500 Fish Total

Step-by-step explanation:

The 2:3 ratio means that for every 2 small fish sold, 3 large fish are sold.

We can divide 600 by 2 and then multiply by 3 to find our answer.

$3(\frac{600}{2} )$

$3(300)$

$900$

To check our answer, we can put it into the form of a fraction and see if it simplifies back to that ratio.

$\frac{600}{900} /\frac{300}{300} =\frac{2}{3}$

We have confirmed 900 is the correct number of large fish. To answer the second part of the question we just have to add the two numbers together.

$600+900=1500$

So, our two answers are

900 Large Fish

1500 Fish Total

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2 years ago

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Step-by-step explanation:

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3 years ago

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Sergeeva-Olga [200]

Answer: 10.00%

Step-by-step explanation:

With no other data, assuming equal attendance it's 1/5 that it's a visitor to Museum 3, and 1/2 that it's a man. So 1/5 × 1/2 = 1/10

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3 years ago

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Is quadrilateral jklm the result of a dilation of quadrilateral abcd by a scale factor of 2? why or why not?

4vir4ik [10]

No. Because sides JM and KL have different slopes from sides AD and BC .

The formula of a slope:

$m=\dfrac{y_2-y_1}{x_2-x_1}$

For AD:

We have the points A(2, -2) and D(1, -4). Substitute:

$m=\dfrac{-4-(-2)}{1-2}=\dfrac{-2}{-1}=2$

For JM:

We have the points J(4, -4) and M(2, -9). Substitute:

$m=\dfrac{-9-(-4)}{2-4}=\dfrac{-5}{-2}=2.5$

$2\neq2.5$

----------------------------------------

Another argument.

No. Because the MJ is not twice as long as AD.

The formula of the length of a segment:

$d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}$

The length of AD:

$|AD|=\sqrt{(1-2)^2+(-4-(-2))^2}=\sqrt{(-1)^2+(-2)^2}=\sqrt{1+4}=\sqrt5$

The length of MJ:

$|MJ|=\sqrt{(2-4)^2+(-9-(-4))^2}=\sqrt{(-2)^2+(-5)^2}=\sqrt{4+25}=\sqrt{29}$

$\sqrt{29}\neq2\sqrt5$

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4 years ago

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4 years ago

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