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crimeas [40]
3 years ago
9

if the cost of a dress is multiplied by 5/8 the price then becomes $30.00 what was the original price

Mathematics
1 answer:
Alik [6]3 years ago
6 0
Let's label the original price of the dress as x. We know that
x \times  \frac{5}{8}  = 30
so that means that we can find x by dividing both sides by 5/8:
x = 30   \div  \frac{5}{8}
A simple rule for dividing fractions is 'Keep Change Flip'. You keep the first number/fraction the same, you change the ÷ to a × and you flip the second fraction. Through this rule, we can now solve the equation much more easily:
x = 30 \times  \frac{8}{5}  \\ x =  \frac{240}{5} \\ x = 48
Therefore, the original price of the dress was $48
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What is the sale price of a $825 tablet that has a 1/4 discount
bogdanovich [222]

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2 years ago
Read 2 more answers
1/2% of 4000 miles<br> Find percent please and show work
bonufazy [111]

Answer:

  20 miles

Step-by-step explanation:

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Here, you want 1/2% × 4000. The associative property of multiplication lets you rearrange this to ...

  (1/2)% × 4000 = (1/2) × 1% × 4000

  = 1/2 × (1/100 × 4000) = 1/2 × 4000/100

  = 1/2 × 40 = 20 . . . miles

_____

If you refuse to be intimidated by percentages, you can do this math in your head.

3 0
3 years ago
Find z 1 z 2 if z 1 = 3(cos37° + isin37°) and z 2 = (cos53° + isin53°
Mashutka [201]

Answer:

Z_{1} Z_{2}  = 3 i

Step-by-step explanation:

<u>Step(i)</u>:-

Given z 1 = 3(cos 37° + i sin 37°)

          z 2 = (cos 53° + i sin 53°)

by using complex numbers

      Z_{1} = r_{1} ( cos\alpha_{1}  + isin\alpha_{1}  ) = r_{1} cis\alpha _{1}

      Z_{2} = r_{2} ( cos\alpha_{2}  + isin\alpha_{2}  ) = r_{2} cis\alpha _{2}

<u><em>step(ii)</em></u>:-

now

   Z_{1} Z_{2} = r_{1} r_{2} cis (\alpha _{1} + \alpha _{2})

       z ₁ = 3(cos 37° + i sin 37°) = 3 c i s 37°

       z ₂ = (cos 53° + i sin 53°) = c i s 53°

we will use formula

     Z_{1} Z_{2} = r_{1} r_{2} cis (\alpha _{1} + \alpha _{2})

     Z_{1} Z_{2} = 3 X 1 cis (37 + 53) = 3cis (90) = 3 cis(\frac{\pi }{2} )

    Z_{1} Z_{2} = 3(cos(\frac{\pi }{2} ) + isin(\frac{\pi }{2}))

    Z_{1} Z_{2} = 3(0 + i (1)) = 3 i

<u><em> Conclusion:</em></u>-

       Z_{1} Z_{2}  = 3 i

       

 

     

5 0
3 years ago
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