Less than. :) Hope this helped
Step-by-step explanation:
DB length = 5 1/4 + 2/3
=21/4 + 2/3
= 63/12 + 8/12 = 71/12
CD length = 5 1/4 -2 = 3 1/4
Let the number of pepperoni pizzas be x
pepperoni = x
veggie = x - 8 [<span>There were eight fewer veggie than pepperoni]
</span>combo = 3x [T<span>here were three times as many combo as pepperoni]
</span>
Given that the total Pizza: 112
x + x - 8 + 3x = 112
5x - 8 = 112
5x = 112 + 8
5x = 120
x = 24
x= 24
x - 8 = 16
3x = 72
So there were 24 pepperoni pizza, 16 veggie pizza and 72 combo pizza
The answr is A sorry if wrong
Answer:
The probability that a performance evaluation will include at least one plant outside the United States is 0.836.
Step-by-step explanation:
Total plants = 11
Domestic plants = 7
Outside the US plants = 4
Suppose X is the number of plants outside the US which are selected for the performance evaluation. We need to compute the probability that at least 1 out of the 4 plants selected are outside the United States i.e. P(X≥1). To compute this, we will use the binomial distribution formula:
P(X=x) = ⁿCₓ pˣ qⁿ⁻ˣ
where n = total no. of trials
x = no. of successful trials
p = probability of success
q = probability of failure
Here we have n=4, p=4/11 and q=7/11
P(X≥1) = 1 - P(X<1)
= 1 - P(X=0)
= 1 - ⁴C₀ * (4/11)⁰ * (7/11)⁴⁻⁰
= 1 - 0.16399
P(X≥1) = 0.836
The probability that a performance evaluation will include at least one plant outside the United States is 0.836.