1. What is the first step when calculating the molar mass of a compound?

Which of the following has an incomplete octet in the lewis structure?

disa [49]

"NO" is the one among the following choices given in the question that has an incomplete <span>octet in the Lewis structure. The correct option among all the options that are given in the question is the fifth option or the last option or option "E". I hope that this is the answer that has come to your help.</span>

4 0

3 years ago

In chemistry, a mole is the amount of any substance that contains the same number of

fredd [130]

Jesus you live me to to much oh oh hey y’all hjmOi. 1234893

6 0

3 years ago

Which statement is true about the rotational period of the moon?

natima [27]

Less than the revolution perilous around earth

4 0

3 years ago

Give the name and formula of the compound formed from the following elements: a) Sodium and nitrogen b) Oxygen and strontium c)

elena-s [515]

Answer: a) Sodium and nitrogen : $NaN_3$ : sodium nitride.

b) Oxygen and strontium : $SrO$ : strontium oxide.

c) Aluminum and chlorine : $AlCl_3$ : aluminium chloride.

d) Cesium and bromine : $CsBr$ : cesium bromide.

Explanation:

For formation of a neutral ionic compound, the charges on cation and anion must be balanced. The cation is formed by loss of electrons by metals and anions are formed by gain of electrons by non metals.

a) Sodium and nitrogen : Here sodium is having an oxidation state of +1 called as $Na^{+}$ cation and nitrogen forms an anion $N^{3-}$ with oxidation state of -3. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $NaN_3$ named as sodium nitride.

b) Oxygen and strontium : Here strontium is having an oxidation state of +2 called as $Sr^{+}$ cation and oxygen forms an anion $O^{2-}$ with oxidation state of -2. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $SrO$ named as strontium oxide.

c) Aluminum and chlorine : Here aluminium is having an oxidation state of +3 called as $Al^{3+}$ cation and chlorine forms an anion $Cl^{-}$ with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $AlCl_3$ named as aluminium chloride.

d) Cesium and bromine : Here cesium is having an oxidation state of +1 called as $Cs^{+}$ cation and bromine forms an anion $Br^{-}$ with oxidation state of -1. Thus they combine and their oxidation states are exchanged and written in simplest whole number ratios to give neutral $CsBr$ named as cesium bromide.

7 0

3 years ago

consider the following equation ch4(g)+2o(g) co2(g)+2h2o(g) how many moles of oxygen are needed for the complete combustion of 3

maria [59]

The answer is 6 moles.

Since the mole ratio of ch4 to o is 1:2, and we have 3 moles of ch4, we can just multiple 3 moles by 2 and get 6 moles

3 0

3 years ago