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3 years ago

Why does H2 is form more quickly than Cl2?

Chemistry

1 answer:

BigorU [14]3 years ago

8 0

Is it because the bonds between hydrogen molecules for easier than bonds between chlorine molecules?

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15. All the following would be a good way to check the validity of web information EXCEPT

sukhopar [10]

Answer:

looking up the organization providing the information

Explanation:

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3 years ago

What is the wavelength if the frequency is 29.2 hz?

ZanzabumX [31]

Answer : The wavelength is $1.027\times 10^7m$

Solution : Given,

frequency = 29.2 Hz

Formula used :

$\nu=\frac{c}{\lambda}\\\lambda=\frac{c}{\nu}$

where,

$\nu$ = frequency

$\lambda$ = wavelength

c = speed of light = $3\times 10^8m/s$

Now put all the given values in this formula, we get the wavelength.

$\lambda=\frac{3\times 10^8m/s}{29.2Hz}=0.1027\times 10^8m=1.027\times 10^7m$ $(1Hz=1s^{-1})$

Therefore, the wavelength is $1.027\times 10^7m$

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3 years ago

What should Molly do to treat her burn?

sp2606 [1]

Molly should put aloe cream on it

4 0

3 years ago

Read 2 more answers

Write a balanced chemical equation depicting the formation of one mole of H2O2(g) from its elements in their standard states.

I am Lyosha [343]

Answer:

$H_2(g)+O_2(g)\rightarrow H_2O_2(g)$

Explanation:

Hello!

In this case, since the formation reaction of a compound is undergone when the pure elements composing it are combined, for gaseous hydrogen peroxide, gaseous diatomic hydrogen and oxygen (standard state) must be combined in order to obtain the gaseous hydrogen peroxide as shown below:

$H_2(g)+O_2(g)\rightarrow H_2O_2(g)$

Whereas it is proved there are two hydrogen and oxygen atoms at each side of the chemical equation and therefore it is balanced.

Best regards!

7 0

3 years ago

A solution contains [Ba2+] = 5.0 × 10−5 M, [Zn2+] = 2.0 × 10−7 M, and [Ag+] = 3.0 × 10−5 M. Sodium oxalate (Na2C2O4) is slowly a

Jet001 [13]

Answer:

BaC₂O₄, then ZnC₂O₄, then Ag₂C₂O₄

Explanation:

1. Calculate the equilibrium concentrations of oxalate ion

Let [C₂O₄²⁻] = c

(a) Barium oxalate

BaC₂O₄ ⇌ Ba²⁺ + C₂O₄²⁻

E/mol·L⁻¹: 5.0 × 10⁻⁵ c

Ksp = [Ba²⁺][C₂O₄²⁻] = 5.0 × 10⁻⁵c = 1.5 × 10⁻⁸

c = (1.5 × 10⁻⁸)/(5.0 × 10⁻⁵) = 3.0 × 10⁻⁴ mol·L⁻¹

(b) Zinc oxalate

ZnC₂O₄ ⇌ Zn²⁺ + C₂O₄²⁻

E/mol·L⁻¹: 2.0 × 10⁻⁷ c

Ksp = [Zn²⁺][C₂O₄²⁻] = 2.0 × 10⁻⁷c = 1.35 × 10⁻⁹

c = (1.35 × 10⁻⁹)/(2.0 × 10⁻⁷) = 6.8 × 10⁻³ mol·L⁻¹

(c) Silver oxalate

Ag₂C₂O₄ ⇌ 2Ag⁺ + C₂O₄²⁻

E/mol·L⁻¹: 3.0 × 10⁻⁵ c

Ksp = [Ag⁺]²[C₂O₄²⁻] = (3.0× 10⁻⁵)²c = 9.0 × 10⁻¹⁰c = 1.1 × 10⁻¹¹

c = (1.1 × 10⁻¹¹)/(9.0 × 10⁻¹⁰) = 0.012 mol·L⁻¹

2. Decide the order of precipitation

BaC₂O₄ will precipitate when c > 3.0 × 10⁻⁴ mol·L⁻¹

ZnC₂O₄ will precipitate when c > 6.8 × 10⁻³ mol·L⁻¹

Ag₂C₂O₄ will precipitate when c > 0.028 mol·L⁻¹

This happens to be the order of increasing concentration of oxalate ion.

The order of precipitation is

BaC₂O₄, then ZnC₂O₄, then Ag₂C₂O₄

4 0

3 years ago