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Kruka [31]
4 years ago
9

Is this statement true or false? Lemonade crystals added to hot water will dissolve faster than when added to cold water. true f

alse
Chemistry
2 answers:
Afina-wow [57]4 years ago
3 0

Hello there.

The answer here is true. Cold objects melt faster in hot water than cold water.

Bad White [126]4 years ago
3 0

True!


Lemonade crystals added to hot water will dissolve faster than when added to cold water.

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What’s the effect of drinking on the digestive system?
AveGali [126]

Alcohol consumption can damage the digestive system and can increase the risk of alcohol-caused cancer and liver disease.

3 0
3 years ago
can anyone help me with this and if my score is perfect i will brainlist u and follow you and please the answer must be the righ
mario62 [17]

Answer:

1.CL

2.SP

3.CL

4.SL

5.SL

6.SP

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Explanation:

HOPE ITS HELP

5 0
3 years ago
From this list below, select the items which are properties of ionic compounds. * 5 points low melting point conductors of elect
e-lub [12.9K]

Answer:

conductors of electricity when in liquid or aqueous state

high melting point

soluble in water

Explanation:

An ionic substance is any substance that is composed of two ions of opposite charge.

In the solid state, ionic substances do not conduct electricity because the ions are trapped inside the crystal. When in liquid state or in aqueous solution, these ions are now free and the solution becomes an electrolyte.

All ionic substances have a very high melting point and dissolve in water easily.

7 0
3 years ago
How can I get the percentage recovery?
frosja888 [35]
If you collected 7.0 grams of something the percentage recovery would be 70% (7/10 x 100).
^
^
^
A percentage recovery is something like that
3 0
3 years ago
The complete combustion of 0.521 g of a snack bar in a calorimeter (Ccal = 6.15 kJ/°C) raises the temperature of the calorimeter
slega [8]
The food raises the temperature of the calorimeter by 1.29 °C. The amount of calorie produced by the combustion would be: 1.29°C * <span> 6.15 kJ/°C= 7.9335 kJ.

If the food weight is </span>0.521g, then the food value would be: 
7.9335 kJ/ 0.521g / (4.184kcal/kJ) =
(15.227 kJ/g) / (4.184kcal/kJ)= 3.64 kilo calorie/gram
6 0
4 years ago
Read 2 more answers
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