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Helga [31]
3 years ago
9

How would i balance this equation?

Chemistry
1 answer:
Anna71 [15]3 years ago
6 0
Our coefficients would be:
C12H22O11: 1
O2: 12
CO2: 12
H2O: 11

Why?
With the coefficients, our reactants would be:
12 carbons, 22 hydrogens, and 35 oxygens.

To obey the law of conservation of mass, we would have to have an equal amount of each of those elements on the products side, since so much of that element needs to form an equal amount on the other side.

So, with those coefficiens, our products would be:
12 carbons total, 35 oxygens total, and 22 hydrogens total. If we compare to the reactants side, they are all equal!

And, since 1 or 11 cannot be simplifyed any smaller, we know the equation is completely balanced.

Hope I could help!
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if i add water to 100 mL of a 0.75 M NaOH solution un til the final volume is 165mL what will the molarity of the diluted soluti
ehidna [41]
Answer is: <span>the molarity of the diluted solution 0,454 M.
</span>V₁(NaOH) = 100 mL ÷ 1000 mL/L = 0,1 L.
c₁(NaOH) = 0,75 M = 0,75 mol/L.
n₁(NaOH) = c₁(NaOH) · V₁(NaOH).
n₁(NaOH) = 0,75 mol/L · 0,1 L.
n₁(NaOH) = 0,075 mol
n₂(NaOH) = n₁(NaOH) = 0,075 mol.
V₂(NaOH) = 165 mL ÷ 1000 mL/L = 0,165 L.
c₂(NaOH) = n₂(NaOH) ÷ V₂(NaOH).
c₂(NaOH) = 0,075 mol ÷ 0,165 L.
c₂(NaOH) = 0,454 mol/L.
7 0
3 years ago
What is the molarity of a solution that contains 15.0g of naoh per 500.0 ml of solution ​
VARVARA [1.3K]

Answer:

0.4 M

Explanation:

Molarity is defined as moles of solute, which in your case is sodium hydroxide,  

NaOH

, divided by liters of solution.

molarity

=

moles of solute

liters of solution

Notice that the problem provides you with the volume of the solution, but that the volume is expressed in milliliters,  

mL

.

Moreover, you don't have the number of moles of sodium hydroxide, you just have the mass in grams. So, your strategy here will be to

determine how many moles of sodium hydroxide you have in that many grams

convert the volume of the solution from milliliters to liters

So, to get the number of moles of solute, use sodium hydroxide's molar mass, which tells you what the mass of one mole of sodium hydroxide is.

7

g

⋅

1 mole NaOH

40.0

g

=

0.175 moles NaOH

The volume of the solution in liters will be

500

mL

⋅

1 L

1000

mL

=

0.5 L

Therefore, the molarity of the solution will be

c

=

n

V

c

=

0.175 moles

0.5 L

=

0.35 M

Rounded to one sig fig, the answer will be

c

=

0.4 M

8 0
3 years ago
What is the covalent<br> bonding of calcium chloride​
algol13

Answer:

<u>Calcium chloride does not have a covalent bond , it is an ionic bond (which means donation of electrons takes place )</u>. The charge of calcium ions is +2, while the charge of sodium ions is -1. The molecule of calcium chloride contains one calcium ion (+2) and two chloride ions (-1), resulting in an overall charge of 0, or neutral.

<u>IONIC BONDING IN CALCIUM CHLORIDE</u> (CaCl_2)

Electron sharing produces covalent compounds, while electron donation produces ionic compounds. CaCl_2 is a salt with an ionic bond. This is because calcium takes up an electron to each of the chlorine atoms, resulting in Ca^2^+ions for calcium andCl^- ions for chlorine. At room temperature, it behaves like a normal ionic halide and is solid. Calcium is a metal with a non-metal sulphate bond.

<u>Thus , Calcium chloride have ionic bonds present on them . No covalent bonds takes place in calcium chloride.</u>

5 0
3 years ago
A quantity of CO gas occupies a volume of 0.64 L at 0.90 atm and 307 K . The pressure of the gas is lowered and its temperature
levacccp [35]

This is an incomplete question, here is a complete question.

A quantity of CO gas occupies a volume of 0.48 L at 1.6 atm and 282 K. The pressure of the gas is lowered and its temperature is raised until its volume is 2.1 L. Find the density of the CO under the new conditions?

Answer : The density of the CO under the new conditions is, 0.213 g/L

Explanation :

First we have to determine the moles of CO gas by using ideal gas equation.

PV=nRT

where,

P = pressure of gas = 0.90 atm

V = volume of gas = 0.64 L

T = temperature of gas = 3 07 K

R = gas constant = 0.0821 L.atm/mol.K

n = number of moles of gas = ?

Now put all the given values in the above formula, we get:

(0.90atm)\times (0.64L)=n\times (0.0821L.atm/mol.K)\times (307K)

n=0.0228mol

Now we have to calculate the mass of CO gas.

\text{ Mass of }CO=\text{ Moles of }CO\times \text{ Molar mass of }CO

Molar mass of CO = 28g/mole

\text{ Mass of }CO=(0.0228moles)\times (28g/mole)=0.638g

Now we have to calculate the density of CO gas.

\text{Density of CO gas}=\frac{\text{Mass of CO gas}}{\text{Volume of CO gas}}

\text{Density of CO gas}=\frac{0.638g}{3.0L}=0.213g/L

Therefore, the density of the CO under the new conditions is, 0.213 g/L

4 0
3 years ago
I'm lyrics texting my crush and want to know what song i should do
GrogVix [38]

Answer:

maybe a love or funny song will be good..

7 0
2 years ago
Read 2 more answers
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