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Helga [31]
3 years ago
9

How would i balance this equation?

Chemistry
1 answer:
Anna71 [15]3 years ago
6 0
Our coefficients would be:
C12H22O11: 1
O2: 12
CO2: 12
H2O: 11

Why?
With the coefficients, our reactants would be:
12 carbons, 22 hydrogens, and 35 oxygens.

To obey the law of conservation of mass, we would have to have an equal amount of each of those elements on the products side, since so much of that element needs to form an equal amount on the other side.

So, with those coefficiens, our products would be:
12 carbons total, 35 oxygens total, and 22 hydrogens total. If we compare to the reactants side, they are all equal!

And, since 1 or 11 cannot be simplifyed any smaller, we know the equation is completely balanced.

Hope I could help!
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Part B
sashaice [31]

The anticodons corresponding to the codons on the mRNA (from part A) is 5' CGA - AAA - GUU 3'.

<h3>What are anticodons?</h3>

Anticodons are nucleotide sequences on tRNA molecules that are complementary to the codons found on mRNA molecules.

The anticodons on tRNA molecules determine the amino acid that is carried by the tRNA.

Just like codons, anticodons occur in triplets of nucleotide sequences.

Considering the codons on the mRNA molecule:

3’ GCT | TTT | CAA | AAA ’5

The complementary anticodon will be:

5' CGA - AAA - GUU 3'

Learn more about anticodons at:brainly.com/question/28067314

#SPJ1

7 0
1 year ago
When .50 mL of 2.0M Li3PO4 is added to 50 mL of 1.0 M LiH2PO4 what is the resulting concentration of Li+?
jeka57 [31]
Hence the resulting concentration of Li+ is 1M. Hope it helps.

8 0
3 years ago
Please help! I don't get this one!!
Aneli [31]
Ph = A
Acid = C
Base = D
Litmus paper = B
Term = ?
5 0
4 years ago
Read 2 more answers
A 0. 462 g sample of a monoprotic acid is dissolved in water and titrated with 0. 180 m koh. what is the molar mass of the acid
Len [333]

The molar mass of the acid if 28. 5 ml of the koh solution is required to neutralize the sample is 90.23g/mol.

<h3>For the calculation of molarity of solution</h3>

Molarity = (moles of solute/volume of solution) × 1000

Given,

Molarity of KOH solution = 0.180 M

Volume of solution = 28.5 mL

0.180 = (moles of KOH/ 28.5) × 1000

Moles = (0.18× 28.5)/1000

= 0.00513 mol

<h3>Chemical equation for the reaction</h3>

HA + KOH ------- KA + H2O

1 moles of KOH reacts with 1 moles of HA.

So, 0.00513 moles of KOH react with 0.00513 moles of HA.

<h3>To calculate the molar mass for given number of moles</h3>

Number of moles= given mass/ Molar mass

Given,

Mass of HA = 0.462 g

Moles of HA = 0.00512 mol

0.00512 = 0.462/ Molar mass

Molar mass = 90.23 g/ mol.

Thus the molar mass of HA required to neutralize the 28.5 mL of KOH is 90.23g/mol.

learn more about molar mass or moles:

brainly.com/question/26416088

#SPJ4

3 0
1 year ago
Is mud a heterogeneous or homogeneous mixture?
Lemur [1.5K]

Answer:

Heterogenous

Explanation:

Mud is a mixture of water and soil

8 0
3 years ago
Read 2 more answers
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