The NA+ ion has less electrons and therefore, the positive charge on Na+ is greater, pulling the electrons closer to the nucleus. Therefore, if the electrons move closer to the nucleus the radius will decrease.
Not only this, but the Na ion also drops a valence level because it only has one electron on its outer valence level. Therefore, another solution is that if the valence level drops, the radius drops as well
Hope this helped!!:D
Answer:the other vaiabable
Explanation:
Answer:
118 mL
Explanation:
We can easily calculate the final volume of the solution (V₂) by applying the following mathematical expression:
V₁ x C₁ = V₂ x C₂
⇒ V₂ = V₁ x C₁/C₂
Given:
V₁ = 10 mL
C₁ = 0.65 M
C₂ = 0.055 M
We replace the data in the mathematical expression to calculate V₂:
V₂ = V₁ x C₁/C₂ = 10 ml x (0.65 M)/ (0.055 M) = 118.18 mL ≅ 118 mL
Answer:
Rate = 0.001615 Ms-1
Explanation:
2 NO2 + F2 --> 2 NO2F
The reaction is first order with respect to NO2 and also first order with respect to F2.
The rate law is given as;
Rate = k [NO2] [ F2]
k = 1.58E-4 M-1s-1
[NO2] = 2.84 M
[F2] = 3.60 M
Rate = ?
Inserting the values into the equation, we have;
Rate = 1.58E-4 * 2.84 * 3.60
Rate = 0.001615 Ms-1