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miskamm [114]
3 years ago
8

Amount of sugar in a sugar bowl is 0.75 cups is this discrete or continuous

Chemistry
2 answers:
Vitek1552 [10]3 years ago
8 0


Amount of sugar in a sugar bowl is 0.75 cups

Continuous

Gekata [30.6K]3 years ago
5 0

Answer:

Continuous

Explanation:

The reason behind the amount of sugar being 0.75 cups is continuous is that it is not countable and it is measurable. The continuous variable is the variable that is measurable and have no jumps while the discrete variable is countable and have jumps such that 0,1,2 etc. As we cannot count the 0.75 cups of the amount of sugar and we can measure this amount thus it is a continuous variable.  

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Which of the following surfaces creates the most friction?
Bumek [7]
The correct answer would be 
A) Gravel driveway
This is the answer because if you have ever been to an ice skating rink, you know that you can glide quickly on it and if you fall, then you just continue sliding its basically a big waterside. In a bowling alley and an indoor basket ball court, most of the floors are probably waxed and your shoes don't have much of a grip on the floor. If you have ever fallen on a driveway, you would know that with the amount of force that you land on the driveway and the weight that is used, you create a lot of friction because of your skin rubbing against the driveway and you also have the marks to prove it! 
Hope this helps and have a wonderful day! :)
4 0
3 years ago
Claim The student hopes the samples are gold, which has a density of 19.3 g/cm3 . A local geologist suggested that samples might
spin [16.1K]

Answer:

Pyrite.

Explanation:

In this case, for the given samples, we compute the densities considering that the volume of each sample is computed by the difference between the volume of the water + sample and the volume of water:

\rho_1=\frac{50.25g}{(60.3-50.1)mL}=4.92g/mL\\ \\\rho_2=\frac{63.56g}{(62.5-49.8)mL}=5.01g/mL\\\\\rho_3=\frac{g}{(61.5-50.2)mL}=5.10g/mL\\\\\rho_4=\frac{55.35g}{(56.7-45.6)mL}=4.99g/mL\\\\\rho_5=\frac{74.92g}{(65.3-50.3)mL}=4.99g/mL\\\\\rho_6=\frac{67.78g}{(60.8-47.5)mL}=5.10g/mL

Therefore, since the density of the samples are closer to the density of pyrite (5.01 g/cm³) we conclude that the samples are more like to be pyrite.

Best regards.

8 0
3 years ago
How many mL of 0.25 M NaOH would have 0.18 moles of NaOH?
8_murik_8 [283]

Answer:

720 mL

Explanation:

To answer this problem we'll use the <em>definition of molarity</em>:

  • Molarity = moles / liters

With that in mind we can <u>calculate the volume in liters</u>:

  • 0.25 M = 0.18 moles / liters
  • liters = 0.72 L

Finally we<u> convert liters to mL</u>:

  • 0.72 L * 1000 = 720 mL

Thus 720 mL of 0.25 M NaOH would have 0.18 moles of NaOH.

5 0
3 years ago
A sample of helium gas has a pressure of 1.5 atm at 23 C. At what Celsius
Nina [5.8K]

Answer:

180.87 °C

Explanation:

Applying pressure law,

P/T = P'/T'..................... Equation 1

Where P = Initial pressure of helium gas, T = Initial Temperature of helium gas, P' = Final Pressure of helium gas, T' = Final Temperature of helium gas

Make T' the subject of equation 1

T' = P'T/P......................... Equation 2

From the question,

Given: P = 1.5 atm, P' = 2.3 atm, T = 23°C = (23+273)K = 296 K

Substitute these values into equation 2

T' = (2.3×296/1.5)

T' = 680.8/1.5

T' = 453.87 K

T' = 453.87-273

T' = 180.87°C

3 0
3 years ago
Am I really stupid for not knowing this ;-;
soldier1979 [14.2K]

Answer:

A. Gases;nonreactive

Explanation:

No ur not stupid, lol hope this helps!

8 0
3 years ago
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