Which of the following is most likely true about water in chemical systems?

Chemistry

2 answers:

lukranit [14]3 years ago

7 0

Answer:

Water dissociates ionic compounds.- B)

Serhud [2]3 years ago

7 0

<h2>Answer:</h2>

The water plays role in <u>B) dissociation of ionic compounds</u>.

<h2>Explanation:</h2>

The presence of positively charged end and negatively charged end in the molecule is referred as polarity. Increasingly significant, the extremity of water is in charge of successfully dissolving other polar particles, for example, sugars and ionic mixes, for example, salt. Ionic mixes break down in water to shape particles. This is critical to recall in light of the fact that for most natural responses to happen, the reactants must be disintegrated in water.

Since water can break down such huge numbers of basic substances, it is known as the all-inclusive dissolvable. Substances that can't be broken down by water, (for example, oils) are called fat dissolvable and are nonpolar, non-ionic exacerbates that are firmly covalently reinforced.

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A student dissolves 6.2g of aniline c6h5nh2 in 350.ml of a solvent with a density of 1.04/gml . the student notices that the vol

Troyanec [42]

Answer : The correct answer for molarity = 0.19 $\frac{mol}{L}$ and Molality = 0.18 $\frac{mol}{Kg}$ .

Given : Mass of aniline = 6.2 g

Volume of solvent = 350 mL Density of solvent = 1.04 g/mL

1) Molarity : It is defined as number of moles of solute present in Litre of solution . It is expressed as :

$Molarity(M) = \frac{moles of solute(mole)}{volume of solution (L)}$ \

Molairty can be found in following steps :

Step 1 : To calculate mole :

Mole of solute can be calculate using mole formula :

$Mole of solute = \frac{given mass of solute (g)}{molar mass of solute\frac{g}{1 mol}}$

Molar mass of aniline (C₆H₅NH₂) = 93.13 $\frac{g}{1 mol}$

Mass of aniline = 6.2 g

Plugging values in mole formula :

$Mole = \frac{6.2 g}{93.13 \frac{g}{1 mol}}$

Mole = 0.0665 mol

Step 2 : To find volume of solution

Volume of solution = volume of solute + volume of solution

Since addition of aniline does not change final volume , so volume of solvent = volume of solution. Since volume is given in mL , so it need to be converted to L .

1 L = 1000mL

$Volume of solution = \frac{350 mL}{1000mL} * 1 L$