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myrzilka [38]
2 years ago
15

When we make observations or measurements in science this is called the​

Chemistry
1 answer:
satela [25.4K]2 years ago
7 0
It is called the scientific method
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Can someone help me here please i need this :(​
podryga [215]
Start by adding the numbers then divide
7 0
3 years ago
Numbers in scientific notation must be expressed in this form m times 10^n where
enot [183]

Answer:

Hi there I think the awnser is B. or A. lol but im 90% its A.

Explanation:

xoxo hope this helps

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7 0
2 years ago
Aqueous sulfuric acid reacts with solid sodium hydroxide to produce aqueous sodium sulfate and liquid water . If of sodium sulfa
notka56 [123]

Answer:

27%

Explanation:

Hello,

The following information is missing, but I found it: "1.92 g of sodium sulfate is produced from the reaction of 4.9 g of sulfuric acid and 7.8 g of sodium hydroxide" so the undergoing chemical reaction is:

2NaOH+H_2SO_4-->Na_2SO_4+2H_2O

Now, to compute the percent yield, we must first establish the limiting reagent to subsequently determine the theoretical yield of sodium sulfate because the real (1.92g) is already given, thus, we consider the following procedure:

n_{NaOH}=7.8gNaOH*\frac{1molNaOH}{40gNaOH}=0.2molNaOH\\n_{H_2SO_4}=4.9gH_2SO_4*\frac{1molH_2SO_4}{98gH_2SO_4}=0.050molH_2SO_4\\

- The moles of sodium hydroxide that completely react with 0.05 moles of sulfuric acid are:

0.2molNaOH*\frac{1molH_2SO_4}{2molNaOH}=0.098molH_2SO_4

As this number is higher than the previously computed 0.05 moles of available sulfuric acid, one states that the sulfuric acid is the limiting reagent. Now, the theoretical grams of sodium sulfate are found via:

0.05molH_2SO_4*\frac{1molNa_2SO_4}{1mol H_2SO_4} *\frac{142.04gNa_2SO_4}{1molNa_2SO_4} =7.1gNa_2SO_4

Finally, the percent yield turns out into:

Y=\frac{1.92g}{7.1g} *100

Y=27.0%

Best regards.

6 0
3 years ago
True or False?
Archy [21]
True.................
4 0
3 years ago
Which atom has the electron configuration 1s22s22p63s23p63d74s2
bonufazy [111]

Answer:

Cobalt (Co)

Explanation:

3d^7 is the location of Cobalt's last electron.

4 0
3 years ago
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