Answer:
x=30o+n90on∈Z
Step-by-step explanation:
cos2x=sin(90o−2x)=sin(2x−30o)
Which mean 90o−2x=2x−30o+n360o
or 90o−2x+2x−30o=(2n+1)180o
The later cannot be true.
so x=30o+n90on∈Z
Given:
AB is the diameter of a circle.
m∠CAB = 26°
To find:
The measure of m∠CBA.
Solution:
Angle formed in the diameter of a circle is always 90°.
⇒ m∠ACB = 90°
In triangle ACB,
Sum of the angles in the triangle = 180°
m∠CAB + m∠ACB + m∠CBA = 180°
26° + 90° + m∠CBA = 180°
116° + m∠CBA = 180°
Subtract 116° from both sides.
116° + m∠CBA - 116° = 180° - 116°
m∠CBA = 64°
The measure of m∠CBA is 64°.
I a pretty sure it is 228,000 but i am not sure.
Answer:
34
Step-by-step explanation:
Straight lines are 180 degrees, so the angle inside of the triangle next to the 127, is 53 degrees. (180-127= 53)
So to find "x", we need to figure out what the full number is.
59+53 = 112.
180-112= 68.
Now that we have the degree of the full angle, we can make an equation to find x.
x*2 = 68
(Divide 2 from both sides to isolate the variable)
x = 34
I hope this helped!
The equation of a elipse:
The length of the major axis is equal 2a if a > b or 2b if b > a.
We have
therefore the length of the major axis is equal 2 · 7 = 14.
