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2 years ago

What is the mean median and mode of 99, 69, 96, 69, 78. Round to the nearest tenth if necessary

1 answer:

6 0

A median is the middle number of a data set.
To find it put the numbers in order.
78, 69, 69, 96, 99
Then find the middle number
78, 69, *69,* 96, 99

The median is 69

A mode is the number that appears the most in a set of numbers.
78, *69, 69,* 96, 99

The mode is 69

To find the mean or average of a set of numbers, add all the numbers together then divide by the number of numbers there are.
99+69+96+69+78 = 411
411/5 = 82.2

The mean is 82.2

Hope this helped! If you have anymore questions or don't understand, please comment on my profile or DM me. :)

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Given: △ACD, m∠BCA = 60° CB ⊥ AD , m∠BDC = 45° AC = 10 cm. Find: BC and DC

neonofarm [45]

Answer:

See if this will help,

https://www.pmschools.org/site/handlers/filedownload.ashx?moduleinstanceid=701&dataid=3612&FileName=2015%20triangle%20proofs%20answers.pdf

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3 years ago

Is matrix multiplication comutative?

konstantin123 [22]

Answer:

Matrix multiplication is not conmutative

Step-by-step explanation:

The matrix multiplication can be performed if the number of columns of the first matrix is equal to the number of rows of the second matrix

Let A with dimension mxn and B with dimension nxp represent two matrix

The multiplication of A by B is a matrix C with dimension mxp, but the multiplication of B by A is can't be calculated because the number of columns of B is not the number of rows of A. Therefore, you can notice that is not conmutative in general.

But even if the multiplication of AB and BA is defined (For example if A and B are squared matrix of 2x2) the multiplication is not necessary conmutative.

The matrix multiplication result is a matrix which entries are given by dot product of the corresponding row of the first matrix and the corresponding column of the second matrix:

$A=\left[\begin{array}{ccc}a11&a12\\a21&a22\end{array}\right]\\B= \left[\begin{array}{ccc}b11&b12\\b21&b22\end{array}\right]\\AB = \left[\begin{array}{ccc}a11b11+a12b21&a11b12+a12b22\\a21b11+a22b21&a21b12+a22b22\end{array}\right]\\\\BA=\left[\begin{array}{ccc}b11a11+b12a21&b11a12+b12a22\\b21a11+b22ba21&b21a12+b22a22\end{array}\right]$

Notice that in general, the result is not the same. It could be the same for very specific values of the elements of each matrix.

6 0

2 years ago

10 points! How do I factor 8x^2-26x+15

Rufina [12.5K]

The AC method, also known as splitting the middle, can be shown like this:

8x^2 - 26x + 15

Check factors of 120.

1 * 120

-1 * -120

2 * 60

-2 * -60

3 * 40

-3 * -40

5 * 24

-5 * -24

6 * 20

-6 * -20 (these factors, when added together, are equal to the middle term, and thus splitting the middle term is possible.)

Split the middle term.

8x^2 - 6x - 20x + 15

Group in terms of 2.

(8x^2 - 6x) - (20x + 15)

Factor each binomial.

2x(4x - 3) - 5(4x - 3)

Rearrange the terms.

(2x - 5)(4x - 3)

6 0

3 years ago

Read 2 more answers

At 6:00 PM, a flagpole that is 35 feet tall casts a shadow that is 50 feet long. At the same time, how long will a person's shad

sertanlavr [38]

Answer:

The length of the person’s shadow is 5.7ft

Explanation:

Length of the flagpole =a= 35ft

Length of the shadow of the flagpole= b=50ft

Length of the person=c= 4ft

Suppose the length of the person’s shadow is=d

According to the rules of trigonometry

$\frac{\text { Length of the flagpole }}{\text { Length of the shadow of the flagpole }}=\frac{\text { Length of the person }}{\text { Length of the person's shadow }}$