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strojnjashka [21]
3 years ago
14

A recent survey 55% of pet owners have more than one pet. if they were 620 pet owner surveyed which proportion can be used to fi

nd the number on more than one pet
Mathematics
1 answer:
rusak2 [61]3 years ago
6 0
Answer is 100/55 = n/620  Reasoning is the percentage has a max of 100 and you do is 100/55 = to the number for N/620 
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Complete the equation of this circle:
adell [148]

Answer:

9

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
The annual precipitation amounts in a certain mountain range are normally distributed with a mean of 104 inches, and a standard
dsp73

Answer:

91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Central limit theorem:

The Central Limit Theorem estabilishes that, for a random variable X, with mean \mu and standard deviation \sigma, the sample means with size n of at least 30 can be approximated to a normal distribution with mean \mu and standard deviation s = \frac{\sigma}{\sqrt{n}}

In this problem, we have that:

\mu = 104, \sigma = 14, n = 49, s = \frac{14}{\sqrt{49}} = 2

What is the probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

This is the pvalue of Z when X = 106.8. So

Z = \frac{X - \mu}{\sigma}

By the Central Limit Theorem

Z = \frac{X - \mu}{s}

Z = \frac{106.8 - 104}{2}

Z = 1.4

Z = 1.4 has a pvalue of 0.9192

0.9192 = 91.92% probability that the mean annual precipitation during 49 randomly picked years will be less than 106.8 inches

8 0
3 years ago
What is the solution set for the inequality 3(5- x)<5x-17
Nana76 [90]

Answer:

i think the answer is 7

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Solve for X and round to the nearest hundredth
Archy [21]

Answer:

Pretty sure it's 20.24.

Step-by-step explanation:

Since you know the side adjacent to the reference angle and you want to find the side opposite, you're going to need to use tangent, which is opp/adj.

tan(39) = \frac{x}{25}

Find the tangent of 39...

0.8097 is the approximate value. So...

0.8097 = \frac{x}{25}

Now, switch the sides to make it easier.

\frac{x}{25} = 0.8097

Multiply both sides by 25.

x = 20.24

3 0
3 years ago
Cody's Gym charges a $15 fee to join and $30 per month. Tyler's Gym charges a $30 fee to join and $20 per month. Write an inequa
posledela

Answer:

<u>After (3/2) months Tyler's gym would be a better deal.</u>

Step-by-step explanation:

Let x the number of months

Cody's Gym charges a $15 fee to join and $30 per month

y₁= 15 + 30x (1)

Tyler's Gym charges a $30 fee to join and $20 per month

y₂ = 15 + 30x (2)

See the attached figure which represent the graph of y₁ (with blue color) and y₂ (with red color)

The point of intersection between y₁ and y₂ is ( 3/2 , 60)

After 3/2 months Tyler's Gym charges will be less than Cody's Gym charges

So, the inequality will be:

<u>After (3/2) months Tyler's gym would be a better deal.</u>

​

3 0
3 years ago
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