Magnesium hydroxide react with hydrochloride to give magnesium chloride and water
THe word equation
magnesium hydroxide +hydrochroric acid---> Magnesium chloride+water
chemical equation
Mg(OH)2(S) + 2HCl (L)--> Mgcl2(S) + 2H2O(l)
when balancing the equation we count the number of molecules in the reactant side which should balance with molecules in the product side.
Answer:
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Explanation:
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<u>Given:</u>
Mass of ice = mass of water = 5.50 kg = 5500 g
Temperature of ice = -20 C
Temperature of water = 75 C
<u>To determine:</u>
Mass of propane required
<u>Explanation:</u>
Heat required to change from ice to water under the specified conditions is:-
q = q(-20 C to 0 C) + q(fusion) + q (0 C to 75 C)
= m*c(ice)*ΔT(ice) + m*ΔHfusion + m*c(water)*ΔT(water)
= 5500[2.10(0-(-20)) + 334 + 4.18(75-0)] = 3792 kJ
The enthalpy change for the combustion of propane is -2220 kJ/mol
Therefore, the number of moles of propane corresponding to the required energy of 3792 kJ = 1 mole * 3792 kJ/2220 kJ = 1.708 moles of propane
Molar mass of propane = 44 g/mol
Mass of propane required = 1.708 moles * 44 g/mol = 75.15 g
Ans: 75.15 grams of propane must be combusted.
The concentration (in M) of hydroxide ions in a solution at 25°C with a pOH of 3.58 is 2.6 × 10⁻⁴ M.
pOH is the measure of basic nature of a solution by evaluating the [OH⁻] concentration.
It is the negative logarithm of the hydroxide ion concentration.
Given,
pOH = 3.58
Temperature = 25°C = 298K
At 25°C, the relation of pOH and [OH⁻] concentration is as follows:
∴ pOH = -log [OH⁻]
⇒ 3.58 = -log [OH⁻]
⇒log [OH⁻] = -3.58
⇒ [OH⁻] = antilog (-3.58)
⇒[OH⁻] = 2.6 × 10⁻⁴ M
The concentration (in m) of hydroxide ions in a solution at 25.0 °C with a pOH of 3. 58 is 2.6 × 10⁻⁴ M.
Learn more about pOH here, brainly.com/question/17144456
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