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kifflom [539]
3 years ago
7

What is the least number of different colours needed to paint a cube so no adjacent faces have the same colour?

Mathematics
1 answer:
kotegsom [21]3 years ago
4 0
Well, we know that cube has 6 sides

So, the least number of different colors needed to paint a cube so no adjacent faces have the same color is :
At least 3

Hope this helps
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Can someone plz help me with this one problem plzzz!!!
tresset_1 [31]

so, you just use the x's from the table and plug them into the equation to find the y.

y=(1)+9

y=10

y=(2)+9

y=11

y=(3)+9

y=12

y=(4)+9

y=13

i hope this helps :)

6 0
3 years ago
Worth 15 points please answer asap!!!!
ExtremeBDS [4]
So do the opposite of the answer like for example 4 +3\2 and your answer is y
the you do the rest
6 0
4 years ago
5/19,5/8,5/11,5/6 from greatest to least
White raven [17]

Answer:

5/6, 5/8, 5/11, 5/19

Step-by-step explanation:

The larger the denominator, the smaller the sections

3 0
3 years ago
Read 2 more answers
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masha68 [24]

its definitely -2.5........

4 0
3 years ago
If a rectangle has side lengths 5x-y and x+4y what would be the area and perimeter of the rectangle?
Dafna1 [17]

Answer:

<em>Answer is</em><em> </em><em>given</em><em> </em><em>below with explanations</em><em>. </em>

Step-by-step explanation:

given \:  \: l = 5x - y \: and \: \:  b = x + 4y \\ area \: of \: rectangle \:= l \times b \: sq.units \\  = (5x - y)(x + 4y) \\  = 5 {x}^{2}  + 20xy - xy - 4 {y}^{2}  \\  = 5 {x}^{2}  + 19xy - 4 {y}^{2}  \\ perimeter \: of \: rectangle \\  = 2(l + b) \\  = 2(5x - y + x + 4y) \\  = 2(6x + 3y) \\  = 12x + 6y

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

6 0
4 years ago
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