What is the least number of different colours needed to paint a cube so no adjacent faces have the same colour?

1 answer:

4 0

Well, we know that cube has 6 sides

So, the least number of different colors needed to paint a cube so no adjacent faces have the same color is :
At least 3

Hope this helps

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Can someone plz help me with this one problem plzzz!!!

tresset_1 [31]

so, you just use the x's from the table and plug them into the equation to find the y.

y=(1)+9

y=10

y=(2)+9

y=11

y=(3)+9

y=12

y=(4)+9

y=13

i hope this helps :)

6 0

3 years ago

Worth 15 points please answer asap!!!!

ExtremeBDS [4]

So do the opposite of the answer like for example 4 +3\2 and your answer is y
the you do the rest

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4 years ago

5/19,5/8,5/11,5/6 from greatest to least

White raven [17]

Answer:

5/6, 5/8, 5/11, 5/19

Step-by-step explanation:

The larger the denominator, the smaller the sections

3 0

3 years ago

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masha68 [24]

its definitely -2.5........

4 0

3 years ago

If a rectangle has side lengths 5x-y and x+4y what would be the area and perimeter of the rectangle?

Dafna1 [17]

Answer:

Answer is given below with explanations. 

Step-by-step explanation:

$given \: \: l = 5x - y \: and \: \: b = x + 4y \\ area \: of \: rectangle \:= l \times b \: sq.units \\ = (5x - y)(x + 4y) \\ = 5 {x}^{2} + 20xy - xy - 4 {y}^{2} \\ = 5 {x}^{2} + 19xy - 4 {y}^{2} \\ perimeter \: of \: rectangle \\ = 2(l + b) \\ = 2(5x - y + x + 4y) \\ = 2(6x + 3y) \\ = 12x + 6y$

HAVE A NICE DAY!

THANKS FOR GIVING ME THE OPPORTUNITY TO ANSWER YOUR QUESTION. 

6 0

4 years ago