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nlexa [21]
2 years ago
10

selling price is €280 and percentage profit is 40 percent what is the profit in euro's and the cost price?

Mathematics
1 answer:
galina1969 [7]2 years ago
3 0

Answer:

cost = 112

profit= 168

Step-by-step explanation:

280÷100=2.8

2.8×40=112

profit = price - cost

= 280-112

= 168

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Lana71 [14]

Answer:

A is the correct answer.

Step-by-step explanation:

y and x meet on those numbers. And i did the test.

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If x^2+y^2=1, what is the largest possible value of |x|+|y|?
Marianna [84]

If <em>x</em>² + <em>y</em>² = 1, then <em>y</em> = ±√(1 - <em>x</em>²).

Let <em>f(x)</em> = |<em>x</em>| + |±√(1 - <em>x</em>²)| = |<em>x</em>| + √(1 - <em>x</em>²).

If <em>x</em> < 0, we have |<em>x</em>| = -<em>x</em> ; otherwise, if <em>x</em> ≥ 0, then |<em>x</em>| = <em>x</em>.

• Case 1: suppose <em>x</em> < 0. Then

<em>f(x)</em> = -<em>x</em> + √(1 - <em>x</em>²)

<em>f'(x)</em> = -1 - <em>x</em>/√(1 - <em>x</em>²) = 0   →   <em>x</em> = -1/√2   →   <em>y</em> = ±1/√2

• Case 2: suppose <em>x</em> ≥ 0. Then

<em>f(x)</em> = <em>x</em> + √(1 - <em>x</em>²)

<em>f'(x)</em> = 1 - <em>x</em>/√(1 - <em>x</em>²) = 0   →   <em>x</em> = 1/√2   →   <em>y</em> = ±1/√2

In either case, |<em>x</em>| = |<em>y</em>| = 1/√2, so the maximum value of their sum is 2/√2 = √2.

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2 years ago
2 4 8 16 what is the rule and the sixth number in the sequence answers
aleksklad [387]
The sequence is incrementing by
{2}^{n}
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Which is 64.
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3 years ago
ANSWER ASAPP!!!!!!FAST PLZZZZZZ!!!!!!!!!
faltersainse [42]
The answer to your question is c
5 0
3 years ago
Read 2 more answers
Suppose the heights of a population of people are normally distributed with a mean of 65.5 inches and a standard deviation of 2.
kupik [55]

Answer:

a) P(64.2

b) 69.764

Step-by-step explanation:

1) Previous concepts

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".

2) Part a

Let X the random variable that represent the heights of a population, and for this case we know the distribution for X is given by:

X \sim N(65.5,2.6)

Where \mu=65.5 and \sigma=2.6

We are interested on this probability

P(64.2

And the best way to solve this problem is using the normal standard distribution and the z score given by:

z=\frac{x-\mu}{\sigma}

If we apply this formula to our probability we got this:

P(64.2

And we can find this probability on this way:

P(-0.50

And in order to find these probabilities we can find tables for the normal standard distribution, excel or a calculator.

P(-0.50

3) Part b

For this part we want to find a value a, such that we satisfy this condition:

P(X>a)=0.05   (a)

P(X   (b)

Both conditions are equivalent on this case. We can use the z score again in order to find the value a.

As we can see on the figure attached the z value that satisfy the condition with 0.95 of the area on the left and 0.05 of the area on the right it's z=1.64. On this case P(Z<1.64)=0.95 and P(z>1.64)=0.05

If we use condition (b) from previous we have this:

P(X  

P(z

But we know which value of z satisfy the previous equation so then we can do this:

z=1.64

And if we solve for a we got

a=65.5 +1.64*2.6=69.764

So the value of height that separates the bottom 95% of data from the top 5% is 69.764.

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