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goldfiish [28.3K]
3 years ago
10

Balance the equation ? c4h10 (g) + ? o2 (g) → ? co2 (g) + ? h2o (g), using the smallest possible integers. what is the coefficie

nt of c4h10?
Chemistry
1 answer:
max2010maxim [7]3 years ago
7 0
C4H10 (g) + (6.5) O2 (g) --> 4CO2 (g) + 5H2O (g)

Smallest coefficient of C4H10 is 1.

First, balance out the Carbon and Hydrogen atoms as they are limiting.

Second, calculate the number of Oxygen atoms and minus away those found in C4H10.

Divide the number with 2 as oxygen exists as O2. [It is OK to put a fraction in front of the molecule as long as there is 1 atom used in the reaction. ]
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Potassium has an atomic number of 19.
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The correct response would be C. Those in the outermost shell, and of highest electron energy are the valence electrons for potassium.
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4 years ago
¿Cuántos gramos de H2O habrá en 3,0115x1023 moléculas de agua?
jolli1 [7]

Answer : The weight of water is 9 g

Explanation:

According to avogadro's law, 1 mole of every substance weighs equal to its molecular mass and contains avogadro's number 6.023\times 10^{23} of particles.

To calculate the number of moles, we use the equation:

\text{Number of moles}=\frac{\text{Given molecules}}{\text{avogadro's number}}=\frac{3.0115\times 10^{23}}{6.023\times 10^{23}}=0.5moles&#10;

1 mole of water (H_2O) weighs = 18 g

0.5 moles of water(H_2O) weighs = \frac{18}{1}\times 0.5=9g

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6 0
3 years ago
The half life for the radioactive decay of carbon- to nitrogen- is years. Suppose nuclear chemical analysis shows that there is
ivann1987 [24]

Answer:

Age of rock = 6.12 × 10³ years

Note: The question is incomplete.A similar but complete question is given below.

The half-life for the radioactive decay of carbon-14 to nitrogen-14 is 5.73 x 10^3 years. Suppose nuclear chemical analysis shows that there is 0.523mmol of nitrogen-14 for every 1.000 mmol of carbon-14 in a certain sample of rock.

Calculate the age of the rock. Round your answer to 2 significant digits.

Explanation:

The half-life of a radioactive material is the time taken for half the atoms in the atomic nucleus of a material to disintegrate.

The half-life for the radioactive decay of carbon-14 to nitrogen-14 is given as 5.73 x 10³ years. This means that given 1 mole of carbon-14 is present initially, after one half-life, 0.5 moles of carbon-14 would remain.

Number of millimoles of carbon-14 remaining = 1 - 0.523 = 0.477 mmol

Number of half-lives that the carbon-14 has undergone is determined as follows:

Amount remaining = (1/2)ⁿ

where nnis number of half-lives

0.5 mmol = one half-life

0.5 = (1/2)¹

O.477 = (1/2)ⁿ = (0.5)ⁿ

㏒₀.₅(0.477) = n

n = ㏒(0.477)/㏒(0.5)

n = 1.067938829

Age of the rock = number of half-lives × half-life

Age of rock = 1.067938829 × 5.73 × 10³ years

Age of rock = 6.12 × 10³ years

6 0
3 years ago
Which of the following changes will decrease the total amount of gaseous solute able to be dissolved in a liter of liquid water?
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3 0
3 years ago
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