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Nesterboy [21]
3 years ago
13

Examine the statement.

Chemistry
1 answer:
saveliy_v [14]3 years ago
6 0
My view point is that i disagree and that the rules are completely different
You might be interested in
Select all that apply.
deff fn [24]

Answer:

backward, opposite, retrograde

Explanation:

why, i just got it right when i put that.

5 0
2 years ago
What structural units make up metallic solids?
Anettt [7]

Answer:

metal atom

Explanation:

metallic solid has layers makes it soft and it also has electron that can carry charge and conduct electricity.

4 0
3 years ago
If 10.g of AgNo3 is available, what volume of 0.25 M AgNo3 can be prepared
Marianna [84]
The equation is L = m/M
First, covert 10. grams of AgNO3 to moles which is 0.059 moles.
Divide 0.059 moles by 0.25M which is 0.24 liters.
3 0
3 years ago
10) At constant temperature, a mixture containing 0.500 M N2 and 0.800 M H2 in a reaction vessel reaches equilibrium. At equilib
jarptica [38.1K]

Answer:

The answer to the question is;

The equilibrium constant for the reaction is 0.278

Reversibility.

Explanation:

Initial concentration = 0.500 M N₂ and 0.800 M H₂

N₂ (g) + 3·H₂ (g) ⇔ 2·NH₃ (g)

One mole of nitrogen combines with three moles of hydrogen form 2 moles of ammonia

That is 1 mole of ammonia requires 3/2 moles of H₂ and 1/2 moles of N₂

0.150 M of ammonia requires 3/2×0.150 moles of H₂ and 1/2×0.150 moles of N₂

That is 0.150 M of ammonia requires 0.225 moles of H₂ and 0.075 moles of N₂

Therefore at equilibrium we have

Number of moles of Nitrogen = 0.500 M - 0.075 M = 0.425 M

Number of moles of Hydrogen = 0.800 M - 0.225 M = 0.575 M

Number of moles of Ammonia = 0.150 M

K_c = \frac{[NH_3]^2}{[N_2][H_2]^3} = \frac{(0.15)^2}{(0.425)*(0.575)^3}  = 0.278

The kind of reaction is a reversible one as the equilibrium constant is greater than 0.01 which as general guide, all components in a reaction with an equilibrium constant between the ranges of 0.01 and 100 will be present when equilibrium is reached and the chemical reaction will be reversible.

6 0
3 years ago
Read 2 more answers
Pure titanium metal is produced by reaction titanium(IV) chloride with magnesium metal. The equation for the reaction is: TiCl4(
qaws [65]

Answer:

The answer to your question is 1.013 Kg

Explanation:

                     TiCl₄  +  2Mg   ⇒     2MgCl₂   +   Ti

mass of Mg = ?

mass of Ti = 1 kg

Process

1.- Calculate the molar mass of Magnesium and titanium (IV)

    Mg = 24.3 g x 2 = 48.6 g

    Ti = 48 g

2.- Write a proportion (rule of three)

                         48.6 g of Mg -------------  48 g of Ti

                           x                   -------------  1000 g of Ti

                           x = (1000 x 48.6) / 48

3.- Result

                 mass of Magnesium = 1012.5g

                                                    = 1.013 kg      

7 0
3 years ago
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