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Nesterboy [21]
3 years ago
13

Examine the statement.

Chemistry
1 answer:
saveliy_v [14]3 years ago
6 0
My view point is that i disagree and that the rules are completely different
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How far is Louisville from the nearest oil field?​
rjkz [21]

Answer:

anyywhere between 20-23 miles

Explanation:

it depends what type of oil field u mean

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PROMISE I WILL MARK BRAINIEST NOT MUCH TIME
Galina-37 [17]
Your answer would be c 



hope this helps
4 0
3 years ago
If the atomic number of an element is 6 and its mass number is 15, how many neutrons are in the atom's nucleus?
lozanna [386]

Atomic Number is the same as the number of protons in an element.
Mass Number is the number of Protons + Neutrons in an element.

Atomic Number: 6 means 6 Protons
Mass Number: 15 means 15 atoms that are a proton/neutron.
We are given out of the 15 atoms, 6 of them are protons, so the other 9 must be Neutrons.

15 - 6 = 9 so there must be 9 Neutrons.

There are 9 Neutrons in atom's nucleus.

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What type of bond is made between amino acids in the ribosome?
sleet_krkn [62]

Answer:

<em><u>Peptide bonds form between the amino group of the amino acid attached to the A-site tRNA and the carboxyl group of the amino acid attached to the P-site tRNA. The formation of each peptide bond is catalyzed by peptidyl transferase, an RNA-based enzyme that is integrated into the 50S ribosomal subunit.</u></em>

8 0
3 years ago
If 250.0 g of water at 30.0 °C cool to 5.0 °C, how many kilojoules of energy did the water lose?
Y_Kistochka [10]

Answer:

-26.125 kj

Explanation:

Given data:

Mass of water = 250.0 g

Initial temperature = 30.0°C

Final temperature = 5.0°C

Amount of energy lost = ?

Solution:

Formula:

Q = m.c. ΔT

Q = amount of heat absorbed or released

m = mass of given substance

c = specific heat capacity of substance

ΔT = change in temperature

ΔT = T2 - T1

ΔT = 5.0°C - 30.0°C

ΔT = -25°C

Specific heat of water is 4.18 j/g.°C

Now we will put the values in formula.

Q = m.c. ΔT

Q = 250.0 g × 4.18 j/g.°C × -25°C

Q = -26125 j

J to kJ

-26125 j ×1 kj /1000 j

-26.125 kj

5 0
3 years ago
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