Answer:
I didn't understand questions properly. Sorry
NH₃:
N = 8*10²²
NA = 6.02*10²³
n = N/NA = 8*10²²/6.02*10²³ ≈ 1.33*10⁻¹=0.133mol
O₂:
N=7*10²²
NA = 6.02*10²³
n = N/NA = 7*10²²/6.02*10²³ = 1.16*10⁻¹=0.116mol
4NH₃ <span>+ 3O</span>₂ ⇒<span> 2N</span>₂<span> + 6H</span>₂<span>O
</span>4mol : 3mol : 2mol
0.133mol : 0.116mol : 0,0665mol
limiting reactant
N₂:
n = 0.0665mol
M = 28g/mol
m = n*M = 0.0665mol*28g/mol = <u>1,862g</u>
Answer:
let's go to the beach or u will relax lol
Explanation:
sodium atom is neutral while sodium ion is a charged specie with a charge of +1
Answer:
See explanation.
Explanation:
Hello there!
In this case, considering the given information, it is not possible to figure out such order of reaction with respect to water as it is not involved in the given chemical reaction:
2E(g)+ F(g)+O(g)_
However, we can say that the order of reaction is 2 with respect to E (power of 2 in the rate law), 1 with respect to F (power of 1 in the rate law) and 0 with respect to O (power of 0 or not present in the rate law).
Regards!
