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drek231 [11]
3 years ago
13

Given the reaction 2NaOH + H2SO4 = Na2SO4 + 2H2O, what is the total number of grams of NaOH needed to react completely with 196

grams of H2SO4
Chemistry
1 answer:
ollegr [7]3 years ago
3 0

Answer:

160 g of NaOH

Explanation:

Reaction: 2NaOH + H₂SO₄ = Na₂SO₄ + 2H₂O

When a base and an acid react, the produce water and a salt. → Neutralization

In this reaction 2 moles of hydroxide need 1 mol of sulfuric acid to react, it is the same to say that 1 mol of sulfuric acid needs 2 moles of NaOH to react. We convert the mass of sulfuric to moles and we propose the rule of three:

196 g / 98 g/mol = 2 moles

1 mol of sulfuric acid needs 2 moles of NaOH to react

Then 2 moles of sulfuric acid will react with (2 . 2) /1 = 4 moles of NaOH

We convert the moles of base to grams → 4 mol . 40 g /1mol = 160 g

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Is the prime meridian a longitudinal or latitudinal line?
Nesterboy [21]

Answer:

longitudinal

Explanation:

A prime meridian is the meridian (a line of longitude) in a geographic coordinate system at which longitude is defined to be 0°. Together, a prime meridian and its anti-meridian (the 180th meridian in a 360°-system) form a great circle. This great circle divides a spheroid into two hemispheres.

4 0
2 years ago
According to Charles's law, what will happen to the volume of these balloons as temperature
german

Answer:

The volume will decrease and the balloons will be smaller

7 0
2 years ago
Determine the freezing point and boiling point of a solution that has 68.4 g of sucrose
Ymorist [56]

Answer:

Freezing T° of solution = - 3.72°C

Boiling T° of solution =  101.02°C

Explanation:

To solve this we apply colligative properties. Firstly, freezing point depression:

ΔT = Kf . m . i

ΔT = Freezing T° of pure solvent - Freezing T° of solution

Kf = Cryoscopic constant, for water is 1.86 °C/m

m = molality (moles of solute in 1kg of solvent)

i = Ions dissolved in solution

Our solute is sucrose, an organic compound so no ions are defined. i = 1.

Let's determine the moles: 68.4 g . 1mol/ 342g = 0.2 moles

molality = 0.2 mol / 0.1kg of water = 2 m

We replace data: ΔT = 1.86°C/m . 2m . 1

Freezing T° of solution = - 3.72°C

Now, we apply elevation of boiling point: ΔT = Kb . m . i

ΔT = Boiling T° of solution - Boiling T° of  pure solvent

Kf = Ebulloscopic constant, for water is 0.512 °C/m

We replace:

Boiling T° of solution - Boiling T° of pure solvent = 0.512 °C/m . 2 . 1

Boiling T° of solution = 0.512 °C/m . 2 . 1 + 100°C → 101.02°C

6 0
2 years ago
According to table g, which substance forms an unsaturated solution when 80. grams of the substance are stirred into 100. grams
e-lub [12.9K]

A saturated solution is one in which no more solute is able to dissolve in a given solvent at a particular temperature. Some amount of the solute is left undissolved in the solution.

Unsaturated solution has solute in lower proportions than required to form a saturated solution.

Supersaturated solution has solute in amounts greater than a saturated solution.

We can take the help of solubility curve in order to find out the amount of a salt required to prepare a saturated solution of that salt at a particular temperature.

The solubility of KI at 10^{0}C is 136 g/ 100 mL water

The solubility of KNO_{3} at 10^{0}C is 21 g/100 mL water.

The solubility of NaNO_{3} at 10^{0}C is 80 g/100 mL water.

The solubility of NaCl at 10^{0}C is 38 g/ 100 mL water.

So the correct answer will be KI, as it would need 136 g KI / 100 mL water to form a saturated solution at 10^{0}C.So, if we have 80g KI/ 100mL water it would be an unsaturated solution.

4 0
2 years ago
Read 2 more answers
How many molecules of CaCi2 are equivalent to 75.9 grams
horsena [70]
<em>M CaCl₂: 40+(35,5×2) = 111 g/mol</em>


6,02·10²³ molecules ---------- 111g
X molecules --------------------- 75,9g
X = (75,9×<span>6,02·10²³)/111
X = <u>4,116</u></span><span><u>·10²³</u> molecules of CaCl</span>₂

:)
8 0
3 years ago
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