A sample 0. 100 moles of a gas is collected at at STP . 2.24 is the volume of the gas in liters.
The STP means standard temperature and pressure.
At STP,
Temperature = 0 °C =273 K
Pressure = 1 atm
We get value of volume by using ideal gas equation,
PV = nRT
- P is the pressure of the gas = 1 atm
- V is the volume occupied by the gas = ?
- n is the number of the moles = 1 mole
- T is the temperature of the gas = 273 K or 0 °C
- R universal gas constant = 8.31 J/ mole × K
Calculation,
Since, one mole of a gas occupy 22.4 L volume at STP
So, for 0.1 mole volume occupy = 22.4L × 0.1 mole/1 mole = 2.24L
To learn more about volume at STP,
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Density = mass/volume = 316/22.5 = 14.045g/mL.
The radiation emitted is a beta particle with a -1 charge. <span>Beta particles have a </span><span>medium penetrating power. An emission of beta particles requires shielding because of the hazards it pose to humans. Thus, one characteristic of this radiation is that some shielding is required.</span>
In here Oxygen is the central atom. It makes two bonds with
Cl and has two lone pairs. Since, the shape is bent and the hybridization is
sp3. Molecular geometry is a bit dissimilar from hybridization. Hybridization
is reliant on the number of bonds and lone pairs. Since O has two bonds with
Cl, its hybridization is sp3. It is like is this: 1 lone pair/bond = s. 2 lone
pairs/bond = sp 3 lone pairs/bonds = sp2, etc. molecular geometry, you count
the number of bonds and lone pairs. This has two bonds and 2 lone pairs so if
they were all bonds, the molecule would be tetrahedral.
Answer:
The equilibrium expression is:
CoC2O4(s)⇌Co2+(aq)+C2O2−4(aq)
For this reaction:
Ksp = [Co2+][C2O2−4]=1.96×10−8
Explanation:
Batteries will not clot if cobalt ions are removed from its cells. Some blood collection tubes contain salts of the oxalate ion,
C2O2−4
, for this purpose. At sufficiently high concentrations, the calcium
and oxalate ions form solid, CoC2O4·H2O (which also contains water bound in the solid). The concentration of Co2+ in a sample of blood serum is 2.2 × 10–3M. What concentration of
C2O2−4
ion must be established before CoC2O4·H2O begins to precipitate.
CoC2O4 does not appear in this expression because it is a solid. Water does not appear because it is the solvent.
Solid CoC2O4 does not begin to form until Q equals Ksp. Because we know Ksp and [Co2+], we can solve for the concentration of
C2O2−4
that is necessary to produce the first trace of solid:
