$a^2x+(a-8)=(a+8)x\\\\(a+8)x=a^2x+(a-8)\ \ \ \ |subtract\ a^2x\ from\ both\ sides\\\\(a+8)x-a^2x=a-8\\\\(a+8-a^2)x=a-8\ \ \ \ |divide\ both\ sides\ by\ (a+8-a^2)\\\\\huge\boxed{x=\frac{a-8}{a+8-a^2}}\to\huge\boxed{x=\frac{8-x}{a^2-a-8}}$

6 0

2 years ago

Read 2 more answers

Can you help me please here is the image

erica [24]

Answer:

f=u+2

Step-by-step explanation:

math

7 0

2 years ago

Use the table of values to calculate the linear correlation coefficient r. X 4,53,86,162 Y 5,1,13,16

Zielflug [23.3K]

Okay so plug them in to get x and y so use 5 as x and 1 as y

7 0

3 years ago

Solve by factoring c^2=5c

muminat

Hey there!

c² = 5c

Subtract 5c from both sides:

c² - 5c = 5c - 5c

Simplify :

c² - 5c = 0

c = 5 , c = 0

6 0

2 years ago