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max2010maxim [7]
3 years ago
14

What is the scale factor of the dilation? 2 3 1/2 1/3

Mathematics
2 answers:
bazaltina [42]3 years ago
6 0
the answer is 2 for the dilation
babymother [125]3 years ago
3 0
I’m not sure of the answer but check Socratic
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10w + 4w = -84 solve by combining like terms show all steps leading to awnser plz
Ira Lisetskai [31]
10w + 4w = - 84
14w = - 84
w = - 84 : 14
w = - 6  (  answer )
-----------------------------------
10 * (- 6) + 4 * (- 6) = - 84
            - 60 + (- 24) = - 84
                         - 84 = - 84
3 0
3 years ago
Ujalakhan01! Please help me! ASAP ONLY UJALAKHAN01. What's (x-1)(x-1)?
Sauron [17]

Answer:

x^2-2x+1

Step-by-step explanation:

=> (x-1)(x-1)

<u><em>Using FOIL</em></u>

=> x^2-x-x+1

=> x^2-2x+1

3 0
3 years ago
Read 2 more answers
A new test has been developed to detect a particular type of cancer. The test must be evaluated before it is put into use. A med
Troyanec [42]
The tree diagram of the problem above is attached
There are four outcomes of the two events,

First test - Cancer, Second Test - Cancer, the probability is 0.0396
First test - Cancer, Second Test - No Cancer, the probability is 0.0004
First test -  No Cancer, Second Test - There is cancer, the probability is 0.0096
First test - No cancer, Second Test - No cancer, the probability is 0.9054

The probability of someone picked at random has cancer given that test result indicates cancer is  \frac{0.0396}{0.0396+0.0096}= \frac{33}{41}

The probability of someone picked at random has cancer given that test result indicates no cancer is \frac{0.0396}{0.0004+0.9504} = \frac{99}{2377}

7 0
3 years ago
(PLESE HELP) Factor the following expression. Simplify your answer.
mars1129 [50]

The factor of the expression 5p(p + 2)^{\frac{2}{3} }  + 4(p + 2)^{\frac{1}{3} } is(p + 2)^{\frac{2}{3} } (5p^{3}  + 10p^{2}  + 20p + 4)

To answer the question, we need to know what factorization is

<h3>What is factorization?</h3>

Factorization is the process of breaking down an expressing into a simpler form containing its factors.

Since

5p(p + 2)^{\frac{2}{3} }  + 4(p + 2)^{\frac{1}{3} }

Since (p + 2)^{\frac{1}{3} } is common, we factor it out. So, we have

(p + 2)^{\frac{2}{3} } (5p(p + 2)^{2}  + 4)

Expanding the bracket, we have

(p + 2)^{\frac{2}{3} } (5p(p^{2}  + 2p + 4) + 4) = (p + 2)^{\frac{2}{3} } (5p^{3}  + 10p^{2}  + 20p + 4)

So, the factor of the expression 5p(p + 2)^{\frac{2}{3} }  + 4(p + 2)^{\frac{1}{3} } is(p + 2)^{\frac{2}{3} } (5p^{3}  + 10p^{2}  + 20p + 4)

Learn more about factorization here:

brainly.com/question/11579257

#SPJ1

8 0
2 years ago
Can the distributive property be used to rewrite
Harman [31]

Answer:

I think No

Step-by-step explanation:

6 0
3 years ago
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