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sergij07 [2.7K]
3 years ago
7

Which set described below is an example of a continuous data set?

Mathematics
1 answer:
Naddika [18.5K]3 years ago
3 0

Answer:

I think the awnser is d!!!!!

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For what values of p does the equation px = 10 have a solution −5; 1; 20?
shutvik [7]

The values of p for which the equation px = 10 have a solution −5; 1; 20 is -2, 10, \frac{1}{2}

<u>Solution:</u>

Given, equation is px = 10.

We have to find the values of p for which solutions of given equations becomes -5, 1, 20.

We just need to substitute -5, 1, 20 in given equation as x, to values of p.

Now, For -5 ⇒ p(-5) = 10 ⇒ -5p = 10 ⇒ p = -2

For 1 ⇒ p(1) = 10 ⇒ p = 10

For 20 ⇒ p(20) = 10 ⇒ 20p = 10 ⇒ p = \frac{1}{2}

Hence, the values of p are -2, 10, \frac{1}{2} for the solutions -5, 1, 20 respectively.

3 0
4 years ago
What are the coordinates (x, y) at which the graphs of 2x + 3y = 12 and 2x - y = 4 intersect?
krok68 [10]

Step-by-step explanation:

2x+3y=12

2x- y =4

-------------------------------------

subtraction. 4y=8

y=2

putting the value of y=2

2x-y=4

2x-2=4

2x=6

x=3

(3,2)

option A

3 0
3 years ago
Read 2 more answers
19. Find the value of:<br>4/3tan^2 30° + Sin^2 60° – 3Cos^2 30°+ 3tan^2. 60° - 2tan^2 45°​
Julli [10]

9514 1404 393

Answer:

  107/18

Step-by-step explanation:

Your calculator and/or knowledge of trig function values can help you evaluate this.

  = 4/3(1/3) +3/4 -3(3/4) +3(3) -2(1)

  = 4/9 +3/4 -9/4 +9 -2

  = 107/18

___

tan(30°) = 1/√3

tan(45°) = 1

tan(60°) = √3

sin(60°) = cos(30°) = √3/2

7 0
3 years ago
For the lines x=3t, y=1-2t, z=2-3t and x (3, 1, 4) +s(-9, 6, 9) (a) Show that the lines are parallel. (b) Calculate the distance
son4ous [18]

Answer:

Step-by-step explanation:

Given lines in parametric form

line L_1

\frac{x}{3}=\frac{y-1}{-2} =\frac{z-2}{-3}

direction vector of L_1 v_1=

Line L_2

direction vector of L_2 v_2=

therefore

v_2=-3v_1

thus lines are parallel.

(ii)distance between two lines is

L_2 is given by

\frac{x-3}{-9}=\frac{y-1}{6} =\frac{z-4}{9}=s

\frac{x-3}{-3}=\frac{y-1}{2} =\frac{z-4}{3}=3s

\left | \frac{\begin{vmatrix}x_2-x_1 &y_2-y_1 &z_2-z_1 \\ a_1&b_1&c_1 \\ a_2&b_2&c_2\end{vmatrix}}{\sqrt{\left ( a_1b_2-a_2b_1 \right )^2+\left ( b_1c_2-b_2c_1 \right )^2+\left ( c_1a_2-c_2a_1 \right )^2}}\right |

where a_1=3

b_1=-2

c_1=-3

a_2=-9

b_2=6

c_2=9

distance(d)=0 units since value of the matrix

\begin{vmatrix}x_2-x_1 &y_2-y_1 &z_2-z_1\\ a_1&b_1&c_1 \\a_2&b_2 &c_2 \end{vmatrix}

is zero

6 0
3 years ago
Is my answer correct ?
gladu [14]
C is your answer because you count 1 square a block

4 0
4 years ago
Read 2 more answers
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