the domain of the following graph= [-5,10)
Domain :
The domain of a function is the set of its possible inputs, i.e., the set of input values where for which the function is defined. In the function machine metaphor, the domain is the set of objects that the machine will accept as inputs.
For example, when we use the function notation f: R→R, we mean that f is a function from the real numbers to the real numbers. In other words, the domain of f is the set of real numbers R (and its set of possible outputs or codomain is also the set of real numbers R).
To, identify the domain and range of functions by using graphs. Because the domain refers to the set of possible input values, the domain of a graph consists of all the input values shown on the
x-axis. The range is the set of possible output values, which are shown on the
y-axis. Keep in mind that if the graph continues beyond the portion of the graph we can see, the domain and range may be greater than the visible values.
We can observe that the horizontal extent of the graph is -5 to 10, so the domain of f is [-5,10)
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Answer:
The monthly expense is $244.16
Step-by-step explanation:
Given:
automobile insurance= $400
health insurance = $140
life insurance = $450
To find:
The monthly expense =?
Solution:
The automobile insurance is Semiannual premium . so it is paid twice a year
So for a year the total automobile insurance paid is = = $800
The health insurance is monthly premium. it is paid for all 12 months.
Thus the health insure for a year is = = $1680
The life insurance is annual premium. so it is paid once in a year
So for a year the life insurance paid is = $450.
The total expense for a year = 800+ 1680 + 450 = 2930
Then for one month the expense will be = = $244.16
Answer:
b
Step-by-step explanation:
-a-(a-b)
Distribute the negative sign to get -a+a+b
-a cancels out a, and you're left with b.
Answer:
Step-by-step explanation:
0,5l + 1,5 (l + 7) = 0,5l
0,5l + 1,5l + 10.5 = 0,5l
1,5l = -10.5
l = -7
m = -7 -7
m = -14
Answer:
The number is: "
12 ".
____________________________________ Let "x" represent "the unknown number" (for which we wish to solve.
The expression:
x <span>− 6 = 2 ; Solve for "x" ;
</span>
_______________________________________________Method 1) Add "6" to EACH SIDE of the equation;
_______________________________________________ →
x − 6 + 6 = 2 + 6 ;
to get:
→
x = 8 ;
______________________________________________Multiply each side of the equation by "
" ; to isolate "x" on one side of the equation ; and to solve for "x" ;
______________________________________________ →
*
x = 8 *
;
→ x = 8 *
;
=
*
;
=
;
=
;
= <span>
1<span>
2 .</span></span>
______________________________________________ x = 12 .
______________________________________________Method 2)______________________________________________ x − 6 = 2 ; Solve for "x" ;
Add "6" to EACH SIDE of the equation;
_______________________________________________ →
x − 6 + 6 = 2 + 6 ;
to get:
→
x = 8 ;
______________________________________________Multiply each side of the equation by "3" ; to get rid of the "fraction" ;
→ 3 *
x = 8 * 3 ;
→
*
x = 8 * 3 ;
→
x = 8 * 3
→
x = 24 ;
→ 2x = 24 ;
→ Divide each side of the equation by "2" ; to isolate "x" on one side of the equation; & to solve for "x" :
2x / 2 = 24 / 2 ;
x = 12 .
__________________________________________________Method 3).__________________________________________________ x − 6 = 2 ; Solve for "x" ;
_______________________________________________Add "6" to EACH SIDE of the equation;
_______________________________________________ →
x − 6 + 6 = 2 + 6 ;
to get:
→
x = 8 ;
______________________________________________Now, divide each side of the equation by "
" ;
to isolate "x" on one side of the equation; & to solve for "x" ;
___________________________________________________{
x } / {
} = 8 / {
} ;
to get: x = 8 / {
} ;
= 8 * (
;
=
*
;
=
;
=
;
=
12 ;
___________________________________________ x = 12 .
___________________________________________NOTE: Variant: (in "Methods 2 & 3") :
___________________________________________At the point where:
___________________________________________ = 8 * (
) ;
=
*
;
__________________________________________ We can cancel out the "2" to a "1" ; and we can cancel out the "8" to a "4" ;
__________________________________________ {since: "8÷2 = 4" ; and since: "2÷2 =1" } ;
__________________________________________and we can rewrite the expression:
__________________________________________ *
;
__________________________________________as:
*
;
__________________________________________which equals:
__________________________________________→
;
=
;
=
12 .
__________________________________________ x = 12 .
__________________________________________Answer:
The number is: "
12 ".
__________________________________________