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Bess [88]
3 years ago
8

How many grams of Carbon dioxide (CO2) are needed to create a 40M

Chemistry
1 answer:
andre [41]3 years ago
8 0

264 grams of Carbon dioxide (CO2) are needed to create a 40M  solution in 150ml of solution.

Explanation:

Given :

molarity of the solution = 40M

Volume of the solution = 150ml or 0.15 litres after dividing it by 1000

compound is carbon dioxide

atomic mass of CO2 = 44.01 gram/mole

mass of CO2 = ?

moles of Co2 =?

the relation between grams and molarity is given by:

number of moles = \frac{mass}{atomic mass of 1 mole}  equation 1

molarity is given by :

Molarity = \frac{number of moles}{volume in litres}  equation 2

 Putting the value of number of moles in equation 2

molarity = \frac{mass}{atomic mass x volume}

mass = molarity x atomic mass x volume

mass = 40 x 0.15 x 44.01

         = 264 grams

264 grams is the mass of carbon dioxide required to make a solution of 40 M in 150 ml of solution.

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Why does hydrogen naturally form diatomic molecules (H2), whereas helium exists as a single atom (He)?
Dimas [21]

Answer:

Hydrogen is a very reactive element. It doesn't exist as a single atom in nature. Neither do any of the other binary nonmetals -- nitrogen, oxygen, fluorine, chlorine, bromine, and iodine. They're too prone to react with something. They react with each other and form binary molecules because the binary molecules are more stable than single atoms (by a lot!). Compounds with other atoms are even more stable, so hydrogen reacts with oxygen to form water, and chlorine reacts with sodium to form table salt.

Explanation:

5 0
3 years ago
At a given temperature, the equilibrium constant for the formation of HI from H2 and I2 was found to be 29.9. Calculate the equi
evablogger [386]

Answer:

The correct answer is: K'= 0.033.

Explanation:

The formation of HI from H₂ and I₂ is given by:

H₂ + I₂ → 2 HI      K= 29.9

The decomposition of HI is the reverse reaction of the formation of HI:

2 HI → H₂ + I₂     K'

Thus, K' is the equilibrium constant for the reverse reaction of formation of HI. It is calculated as the reciprocal of the equilibrium constant of the forward reaction (K):

K' = 1/K = 1/(29.9)= 0.033

Therefore, the equilibrium constant for the decomposition of HI is K'= 0.033

5 0
4 years ago
Which of the following reagents should be used to convert to Question 26 options: A) H2, Lindlar's catalyst B) Na, liquid NH3 C)
diamong [38]

Answer: The question is is not complete...here is the complete question.

Which of the following reagents should be used to convert 3-Hexyne to E-3-hexene

Option B.

Na, liquid NH3.

Explanation:

3-Hexyne to E-3-hexene can be converted with by using the reagent of Na, NH3 (birch reduction) and this can be done by hdrogenation of H2.

The reagents NaNH3 convert 3-Hexyne to E-3-hexene because it is a reducing agents that convert or has the ability to reduce alkynes to trans alkenes.

3 Hexyne is an alkynes and it is converted to E- 3 hexene Na and NH3.

3 0
3 years ago
If excess sulfuric acid reacts with 30 grams of sodium chloride, how many grams of HCl are produced
vodka [1.7K]
Consider the Chemical Reaction first:

Reaction: H₂SO₄ + 2 NaCl → 2 HCl + Na₂SO₄

Now, Given mass of NaCl = 30 g
Molar mass of Nacl = 58 g/mol

Now, Number of moles of NaCl = 30/58 = 0.517 mol

Balance the equation, For every 2 molecules of NaCl, 2 molecules of HCl formed, so the number of moles would be same.

Hence, Number of moles of HCl = 0.517 mol

Now, Mass of HCl = Molar mass of HCl * Number of moles
Mass = 36 * 0.517    [ Molar mass of HCl = 36 ]
Mass = 18.62 g

In short, Your Answer would be: 18.62 Grams

Hope this helps!
6 0
3 years ago
**<br> H₂ + O2-&gt;<br> Balancing equations from a reaction
goblinko [34]

Answer:

2H2+O2->2H2O

Explanation:

You have to balance the equation, you have 4 hydrogen and 2 oxygen atoms

8 0
3 years ago
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