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horsena [70]
4 years ago
6

a 10.00 gram sample of a soluble barium salt is treated with an excess of sodium sulfate to precipitate 11.21 grams BaSO4, (M= 2

33.4). which barium salt is it?

Chemistry
2 answers:
shtirl [24]4 years ago
5 0
Hope it helps. All the best!

MrRa [10]4 years ago
5 0
For the answer to the question above, first divide the 
BaSo4 and 233.4 and it will look like this.

(11.21 g BaSO4) / (233.4 g/mol BaSO4) = 0.0480 mol BaSO4 and original barium salt 
Then,
<span>(10.0 g) / (0.0480 mol) = 208.3 g/mol </span>
<span>So the answer would be BaCl2.
</span>I hope my answer helped you.
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Answer:

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B. 11,540

<h3>Further explanation </h3>

The atomic nucleus can experience decay into 2 particles or more due to the instability of its atomic nucleus.  

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\large{\boxed{\bold{N_t=N_0(\dfrac{1}{2})^{t/t\frac{1}{2} }}}

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