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3 years ago

If excess sulfuric acid reacts with 30 grams of sodium chloride, how many grams of HCl are produced

1 answer:

6 0

Consider the Chemical Reaction first:

Reaction: H₂SO₄ + 2 NaCl → 2 HCl + Na₂SO₄

Now, Given mass of NaCl = 30 g
Molar mass of Nacl = 58 g/mol

Now, Number of moles of NaCl = 30/58 = 0.517 mol

Balance the equation, For every 2 molecules of NaCl, 2 molecules of HCl formed, so the number of moles would be same.

Hence, Number of moles of HCl = 0.517 mol

Now, Mass of HCl = Molar mass of HCl * Number of moles
Mass = 36 * 0.517 [ Molar mass of HCl = 36 ]
Mass = 18.62 g

In short, Your Answer would be: 18.62 Grams

Hope this helps!

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The expression of the theoretical yield (TY) in function of limiting reagent (LR) of a reaction is as follows: TY = ideal mole r

spin [16.1K]

Answer: The theoretical yield of acetanilide is 6.5 grams.

Explanation:

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For aniline:

Given mass of aniline = $4.50\times 10^0=4.50g$ (We know that: $10^0=1$ )

Molar mass of aniline = 93.13 g/mol

Putting values in equation 1, we get:

$\text{Moles of aniline}=\frac{4.50g}{93.13g/mol}=0.048mol$

For acetic anhydride:

To calculate the mass of acetic anhydride, we use the equation:

$\text{Density of substance}=\frac{\text{Mass of substance}}{\text{Volume of substance}}$

Volume of acetic anhydride = $(1.25\times \text{Mass of aniline})=1.25\times 4.50=5.625mL$

Density of acetic anhydride = 1.08 g/mL

Putting values in above equation:

$1.08g/mL=\frac{\text{Mass of acetic anhydride}}{5.625mL}\\\\\text{Mass of acetic anhydride}=(1.08g/mL\times 5.625mL)=6.08g$

Given mass of acetic anhydride = 6.08 g

Molar mass of acetic anhydride = 102.1 g/mol

Putting values in equation 1, we get:

$\text{Moles of acetic anhydride}=\frac{6.08g}{102.1g/mol}=0.06mol$

The chemical equation for the reaction of aniline and acetic anhydride follows:

$C_6H_5NH_2+CH_3COOCOCH_3\rightarrow C_6H_5NHCOCH_3+CH_3COOH$

By Stoichiometry of the reaction:

1 mole of aniline reacts with 1 mole of acetic anhydride

So, 0.048 moles of aniline will react with = $\frac{1}{1}\times 0.048=0.048mol$ of acetic anhydride

As, given amount of acetic anhydride is more than the required amount. So, it is considered as an excess reagent.

Thus, aniline is considered as a limiting reagent because it limits the formation of product.

By Stoichiometry of the reaction:

1 mole of aniline produces 1 mole of acetanilide

So, 0.048 moles of aniline will produce = $\frac{1}{1}\times 0.048=0.048mol$ of acetanilide

Now, calculating the theoretical yield of acetanilide by using equation 1:

Moles of acetanilide = 0.048 moles

Molar mass of acetanilide = 135.17 g/mol

Putting values in equation 1, we get:

$0.048mol=\frac{\text{Mass of acetanilide}}{135.17g/mol}\\\\\text{Mass of acetanilide}=(0.048mol\times 135.17g/mol)=6.5g$

Hence, the theoretical yield of acetanilide is 6.5 grams.

3 0

3 years ago

How many moles are in 2.04 x 10^8 atoms of calcium?

I am Lyosha [343]

Answer:

2.0 moles

Explanation:

I hope this helps you a little bit at least the answer is 2.0 but if you want to review more stuff check the photos

7 0

2 years ago

How does inertia affect a person who is not wearing a seatbelt during a collision?

olya-2409 [2.1K]

During a collision, the person would most likely experience the same conditions with or without a seatbelt.

5 0

3 years ago

A mixture of gases is analyzed and found to have the following composition in mol %: CO2 12.0 CO 6.0 CH4 27.3 H2 9.9 N2 44.8 a)

vichka [17]

Answer:

a) CO₂: 21,9%; CO: 7,0%; CH₄: 18,2%; H₂: 0,8%; N₂: 52,1%

b) 24,09 g/mol

Explanation:

a) It is posible to obtain the composition of the gas mixture in weight% using molecular mass of each compound, thus:

12% CO₂× $\frac{44,01g}{1mol}$ = 528,1 g

6% CO× $\frac{28,01g}{1mol}$ = 168,1 g

27,3% CH₄× $\frac{16,05g}{1mol}$ = 438,2 g

9,9% H₂× $\frac{2,02g}{1mol}$ = 20,0 g

44,8% N₂× $\frac{28g}{1mol}$ = 1254,4 g

The total mass of the gas mixture is:

528,1g + 168,1g + 438,2g + 20,0g + 1254,4g = 2408,8 g

Thus composition of the gas mixture in weight% is:

CO₂: $\frac{528,1g}{2408,8g}$ ×100 = 21,9%

CO: $\frac{168,1g}{2408,8g}$ ×100 = 7,0%

CH₄: $\frac{438,2g}{2408,8g}$ ×100 = 18,2%

H₂: $\frac{20,0g}{2408,8g}$ ×100 = 0,8%

N₂: $\frac{1254,4g}{2408,8g}$ ×100 = 52,1%

b) The average molecular weight of the gas mixture is determined with mole % composition, thus:

0,12×44,01g/mol + 0,06×28,01g/mol + 0,273×16,05g/mol + 0,099×2,02g/mol + 0,448×28g/mol = 24,09 g/mol

I hope it helps!

6 0

3 years ago

An atom that has 13 protons and 15 neutrons is an isotope of the element? How can I count it?

Diano4ka-milaya [45]

It's simple.
the number of protons in an atom never changes. And also, the no of protons is its atomic number.if you look up the periodic table, you will find a number on the top - left corner of each of the boxes. This is the atomic number.No 2 same elements on the periodic table have the same atomic number. So, all you have to do is search for a box that has the number 13 on it.

and by the way ... the element which you're searching for is Aluminium

7 0

3 years ago