Can someone please help me with this i don’t know what I’m doing.

Olin [163]

So, let's say that all the dogs had a number of x.

then 1/12 x were the Hound Group dogs.

then, out of the Hound Group,, that is 1/12 x, 3/10 were English Foxhounds.

For this, we need to multiply the fractions:

$\frac{1}{12}x* \frac{3}{10} = \frac{3}{120}x =\frac{1}{40}x$

so of all the dogs at the show, the English Foxhunds were a 1/40 fraction,

5 0

3 years ago

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Paulo’s grandfather gave him a collection of 20 coins. Each month Paulo adds 4 coins to his collection. Which inequality can be

Phoenix [80]

Answer:

$4m+20>50$

Step-by-step explanation:

Let <em>m</em> represent the amount of months that has passed.

Paulo started out with 20 coins.

Each month, he adds four more coins to his collection.

Therefore, the amount of coins added after <em>m</em> months will be given by 4<em>m</em>.

So, the amount of coins Paulo has total after <em>m</em> months can be given by:

$4m+20$

We want to know when Paulo will have "more than" 50 coins in his collection. Therefore, we will use the "greater than" sign. Thus, our inequality will be:

$4m+20>50$

4 0

3 years ago

A bicycle tire has a radius of 26 inches. How many revolutions will this tire make if the bicycle is pedaled 1 mile? (Use 3.14 f

Fittoniya [83]

How far does a wheel move when it rotates once? The length of the outside of the tyre? Isn't that the same as the circumference?

4 0

2 years ago

What is the possible number of positive and negative real roots or zeroes in f(x)=x^3+x^2-4

Tanya [424]

This is a third degree polynomial, so we know that the maximum amount of roots will be 3.

We also know that imaginary roots come in pairs, so there is either 0 or 2 imaginary roots.

We can tell the amount of positive / negative roots by applying Descartes' rule of signs.

Let's examine the polynomial: x^3 + x^2 - 4

Note the sign changes.

From left to right, there is one sign change.

We now know there is only one positive real root.

Now, we can replace all values of x with -1 and then simplify. The number of sign changes will tell us the amount of negative roots.

(-1)^3 + (-1)^2 - 4

-1 + 1 - 4

From left to right, there are two sign changes, which tells us there will be 2 or 0 negative roots.

If there are 2, they are not imaginary.

If there are 0, they are imaginary.

<h3>So, our guaranteed root is:</h3><h3>1 positive, real root.</h3><h3>And our possible roots are:</h3><h3>2 negative, real roots.</h3><h3>0 negative, real roots, but 2 imaginary roots.</h3>

3 0

3 years ago

There's another!! 12 points

Morgarella [4.7K]

Answer:

Altogether it costs $6.75

If you pay with a $10, you'll get $3.25 back

Step-by-step explanation:

7 0

3 years ago

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