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Naily [24]
3 years ago
15

Light travels a distance of one mile in about 0.000005368 second.

Mathematics
1 answer:
Alinara [238K]3 years ago
5 0
5 x 10^-6
Five times ten to the negative six
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Tristan had 95 inches of ribbon.He cut off 27.50 inches. How many inches of ribbon remain
tatiyna

Answer:

67.50 inches


Step-by-step explanation:


5 0
3 years ago
F left parenthesis x right parenthesis equals 9 x cubed plus 2 x squared minus 5 x plus 4 and g left parenthesis x right parenth
Jet001 [13]
The answer is 2x(2x²+x+1).

When we subtract polynomials we combine like terms:
(9x³+2x²-5x+4)-(5x³-7x+4)

9x³-5x³=4x³
2x²- 0 = 2x²
-5x--7x=-5x+7x=2x
4-4=0

This gives us 
4x³+2x²+2x

Each of these is divisible by 2, and each has an x, so we factor those out:
2x(                        )

4x³/2x = 2x²:
2x(2x²                   )

2x²/2x=x:
2x(2x²+x               )

2x/2x = 1:
2x(2x²+x+1)
3 0
3 years ago
The value of the expression -2 xy for x = -4.7 and y = 0.2 is _____.
sergeinik [125]

The value of the expression -2xy for x = -4.7 and y = 0.2 is 1.88. Thus option number 3 is correct.

<u>Solution:</u>

We have been given an expression that is -2xy and have been asked to find its value for the given values of x and y

The given values of x and y are -4.7 and 0.2 respectively.

To find the value of the expression for the given values of x and y we substitute the values of x and y in the given expression and solve it as follows:

Given expression = -2xy

\begin{array}{l}{=-2(-4.7)(0.2)} \\\\ {=9.4 \times 0.2} \\\\ {=1.88}\end{array}

Hence the option number 3 is correct.

4 0
3 years ago
Read 2 more answers
Let V denote the set of ordered triples (x, y, z) and define addition in V as in
icang [17]

Answer:

a) No

b) No

c) No

d) No

Step-by-step explanation:

Remember, a set V wit the operations addition and scalar product is a vector space if the following conditions are valid for all u, v, w∈V and for all scalars c and d:

1. u+v∈V

2. u+v=v+u

3. (u+v)+w=u+(v+w).

4. Exist 0∈V such that u+0=u

5. For each u∈V exist −u∈V such that u+(−u)=0.

6. if c is an escalar and u∈V, then cu∈V

7. c(u+v)=cu+cv

8. (c+d)u=cu+du

9. c(du)=(cd)u

10. 1u=u

let's check each of the properties for the respective operations:

Let u=(u_1,u_2,u_3), v=(v_1,v_2,v_3)

Observe that  

1. u+v∈V

2. u+v=v+u, because the adittion of reals is conmutative

3. (u+v)+w=u+(v+w). because the adittion of reals is associative

4. (u_1,u_2,u_3)+(0,0,0)=(u_1+0,u_2+0,u_3+0)=(u_1,u_2,u_3)

5. (u_1,u_2,u_3)+(-u_1,-u_2,-u_3)=(0,0,0)

then regardless of the escalar product, the first five properties are met for a), b), c) and d). Now let's verify that properties 6-10 are met.

a)

6. c(u_1,u_2,u_3)=(cu_1,u_2,cu_3)\in V

7.

c(u+v)=c(u_1+v_1,u_2+v_2,u_3+v_3)=(c(u_1+v_1),u_2+v_2,c(u_3+v_3))\\=(cu_1+cv_1,u_2+v_2,cu_3+cv_3)=c(u_1,u_2,u_3)+c(v_1,v_2,v_3)=cu+cv

8.

(c+d)u=(c+d)(u_1,u_2,u_3)=((c+d)u_1,u_2,(c+d)u_3)=\\=(cu_1+du_1,u_2,cu_3+du_3)\neq (cu_1+du_1,2u_2,cu_3+du_3)=cu+du

Since 8 isn't satify then V is not a vector space with the addition as in R^3 and the scalar product a(x,y,z)=(ax,y,az)

b)  6. c(u_1,u_2,u_3)=(cu_1,0,cu_3)\in V

7.

c(u+v)=c(u_1+v_1,u_2+v_2,u_3+v_3)=(c(u_1+v_1),0,c(u_3+v_3))\\=(cu_1+cv_1,0,cu_3+cv_3)=c(u_1,u_2,u_3)+c(v_1,v_2,v_3)=cu+cv

8.

(c+d)u=(c+d)(u_1,u_2,u_3)=((c+d)u_1,0,(c+d)u_3)=\\=(cu_1+du_1,0,cu_3+du_3)=(cu_1,0,cu_3)+(du_1,0,du_3) =cu+du

9.

c(du)=c(d(u_,u_2,u_3))=c(du_1,0,du_3)=(cdu_1,0,cdu_3)=(cd)u

10

1u=1(u_1,u_2,u3)=(1u_1,0,1u_3)=(u_1,0,u_3)\neq(u_1,u_2,u_3)

Since 10 isn't satify then V is not a vector space with the addition as in R^3 and the scalar product a(x,y,z)=(ax,0,az)

c) Observe that 1u=1(u_1,u_2,u3)=(0,0,0)\neq(u_1,u_2,u_3)

Since 10 isn't satify then V is not a vector space with the addition as in R^3 and the scalar product a(x,y,z)=(0,0,0).

d)  Observe that 1u=1(u_1,u_2,u3)=(2*1u_1,2*1u_2,2*1u_3)=(2u_1,2u_2,2u_3)\neq(u_1,u_2,u_3)=u

Since 10 isn't satify then V is not a vector space with the addition as in R^3 and the scalar product a(x,y,z)=(2ax,2ay,2az).

8 0
3 years ago
Math question please help if you get this right I will mark you as a brainliest
san4es73 [151]

The Law of Cosines would be your best bet here, since the unknown side is opposite the known angle 110 degrees.

|AC|^2 = (8 in)^2 + (23 in)^2 - 2(8 in)(23 in)*cos 110 degrees

= 64 in^2 + 529 in^2 - (368 in^2)*(-0.342)

= 593 in^2 + 126 in ^2 approximately

= 719 in^2 approximately

Then the length of side AC is approx. √(716 in^2) = 27 in

3 0
3 years ago
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