Answer:
The coefficient of static friction is 0.29
Explanation:
Given that,
Radius of the merry-go-round, r = 4.4 m
The operator turns on the ride and brings it up to its proper turning rate of one complete rotation every 7.7 s.
We need to find the least coefficient of static friction between the cat and the merry-go-round that will allow the cat to stay in place, without sliding. For this the centripetal force is balanced by the frictional force.

v is the speed of cat, 

So, the least coefficient of static friction between the cat and the merry-go-round is 0.29.
Answer:
The magnitude of the charge on each sphere is 0.135 μC
Explanation:
Given that,
Mass = 1.0
Distance = 2.0 cm
Acceleration = 414 m/s²
We need to calculate the magnitude of charge
Using newton's second law


Put the value of F

Put the value into the formula





Hence, The magnitude of the charge on each sphere is 0.135μC.
Answer:
<h2>7.5 N</h2>
Explanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question
mass = 2.5 kg
acceleration = 3.0 m/s²
We have
force = 2.5 × 3.0 = 7.5
We have the final answer as
<h3>7.5 N</h3>
Hope this helps you
Answer:
His weight would be 100 N
Explanation:
Answer:
Circuit one will have more current than circuit two
Explanation:
I am assuming that you have to see which circuit has the greater current in this case. Well, this is the perfect example of Ohm's Law, which states the following -
V = IR,
where V = voltage / potential difference, I = current, and R = resistance
If one circuit has twice the voltage and half the resistance of the second circuit, as voltage is directly proportional to the resistance -
2V = I( 1 / 2R ),
4V = IR,
I = 4V / R
Whereas in the second circuit -
V = IR,
I = V / R
As you can note, voltage is directly proportional to the current ( I ) as well as the resistance. The only difference between the two formulas I = 4V / R, and I = V / R is the difference in the voltage. With the voltage being 4 times greater in the first circuit, and current is 4 times greater in the first circuit as well.
<u><em>Hence, circuit one will have more current than circuit two</em></u>