Answer:
41.1 ÷ 40.0
Explanation:
Did you learn about Newton
Answer:
idk search it on google chrome
Explanation:
Answer:
So the specific heat of the liquid B is greater than that of A.
Explanation:
Liquid A is hotter than the liquid B after both the liquids are heated identically for the same duration of time from the same initial temperature then according to heat equation,
![Q=m.c.\Delta T](https://tex.z-dn.net/?f=Q%3Dm.c.%5CDelta%20T)
where:
m = mass of the body
c = specific heat of the body
change in temperature of the body
The identical heat source supplies the heat for the same amount of time then the quantity of heat supplied is also equal.
So for constant heat, constant mass the temperature change is inversely proportional to the specific of heat of the liquid.
![\Delta T=\frac{Q}{m} \times \frac{1}{c}](https://tex.z-dn.net/?f=%5CDelta%20T%3D%5Cfrac%7BQ%7D%7Bm%7D%20%5Ctimes%20%5Cfrac%7B1%7D%7Bc%7D)
![\Delta T\propto\frac{1}{c}](https://tex.z-dn.net/?f=%5CDelta%20T%5Cpropto%5Cfrac%7B1%7D%7Bc%7D)
So the specific heat of the liquid B is greater than that of A.
Answer:
7.6 s
Explanation:
Considering kinematics formula for final velocity as
![v^{2}=u^{2}+2as](https://tex.z-dn.net/?f=v%5E%7B2%7D%3Du%5E%7B2%7D%2B2as)
Where v and u are final and initial velocities, a is acceleration and s is distance moved.
Making v the subject then
![v=\sqrt{u^{2}+2as}](https://tex.z-dn.net/?f=v%3D%5Csqrt%7Bu%5E%7B2%7D%2B2as%7D)
Substituting 8.8 m/s for u, 138 m for s and 2.45 m/s2 for a then
![v=\sqrt{8.8^{2}+2*2.45*138}\\v=27.45 m/s](https://tex.z-dn.net/?f=v%3D%5Csqrt%7B8.8%5E%7B2%7D%2B2%2A2.45%2A138%7D%5C%5Cv%3D27.45%20m%2Fs)
Also, v=u+at and making t the subject of the formula
![t=\frac {v-u}{a}](https://tex.z-dn.net/?f=t%3D%5Cfrac%20%7Bv-u%7D%7Ba%7D)
Substituting 27.45 m/s for v, 8.8 m/s for u and 2.45 m/s for a then
![t=\frac {27.45-8.8}{2.45}=7.6122448979591\approx 7.6s](https://tex.z-dn.net/?f=t%3D%5Cfrac%20%7B27.45-8.8%7D%7B2.45%7D%3D7.6122448979591%5Capprox%207.6s)
Therefore, it needs 7.6 seconds to travel