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amid [387]
3 years ago
8

If an object is moving up, is it considered to have a positive or negative velocity?

Physics
1 answer:
grin007 [14]3 years ago
7 0

Answer:

A positive velocity

Explanation:

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A classic demonstration illustrating eddy currents is performed by dropping a permanent magnet inside a conducting cylinder. The
kvv77 [185]

Answer:

The correct solution is "0.69 N".

Explanation:

The given values are:

Mass of magnet,

m = 70 g

or,

   = 0.07 kg

Width,

= 1.0 cm

Velocity,

= 10 cm/s

Length of the pipe,

= 80 cm

Whenever the velocity is constant, then the net force which is acting on the magnet will be "0".

On the magnet,

The up-ward force will be:

⇒  F=mg

On substituting the values, we get

⇒      =0.07\times 9.8

⇒      =0.69 \ N

4 0
3 years ago
A night lamp uses a 30 W bulb. If it is left on continuously for 8 hours, how much energy will it use?
den301095 [7]

Answer:

Explanation:

30W * 8 h = 240 Wh = 0.240 kWh

6 0
3 years ago
Read 2 more answers
The Berlin marathon is one of the fastest marathons courses; many world records have been set there. In 2014 Dennis Kimetto ran
Mandarinka [93]

Answer:

about 2000 klm per min

Explanation:

7 0
3 years ago
Copper wire of diameter 0.289 cm is used to connect a set of appliances at 120 V, which draw 1850 W of power total. The resistiv
vodka [1.7K]

Answer:

(a) The power wasted for 0.289 cm wire diameter is 15.93 W

(b) The power wasted for 0.417 cm wire diameter is 7.61 W

Explanation:

Given;

diameter of the wire, d = 0.289 cm = 0.00289 m

voltage of the wire, V = 120 V

Power drawn, P = 1850 W

The resistivity of the wire, ρ = 1.68 x 10⁻⁸ Ω⋅m

Area of the wire;

A = πd²/4

A = (π x 0.00289²) / 4

A = 6.561 x 10⁻⁶ m²

(a) At 26 m of this wire, the resistance of the is

R = ρL / A

R = (1.68 x 10⁻⁸  x 26) / 6.561 x 10⁻⁶

R = 0.067 Ω

Current in the wire is calculated as;

P = IV

I = P / V

I = 1850 / 120

I = 15.417 A

Power wasted = I²R

Power wasted = (15.417²)(0.067)

Power wasted = 15.93 W

(b) when a diameter of 0.417 cm is used instead;

d = 0.417 cm = 0.00417 m

A = πd²/4

A = (π x 0.00417²) / 4

A = 1.366 x 10⁻⁵ m²

Resistance of the wire at 26 m length of wire and  1.366 x 10⁻⁵ m² area;

R = ρL / A

R = (1.68 x 10⁻⁸  x 26) / 1.366 x 10⁻⁵

R = 0.032 Ω

Power wasted = I²R

Power wasted = (15.417²)(0.032)

Power wasted = 7.61 W

5 0
3 years ago
atmospheric pressure is measured in all of the following units except ……… ? A. torr B. pascal C. bar D. newton?
AlexFokin [52]

Answer:

C. Bar

Explanation:

6 0
2 years ago
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