The resistance of a lamp that draws 0.5A of current when it is operated by a 12V battery will be Ω
2 answers:
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Answer:
A) E = 4.96 x 10³ eV
B) E = 4.19 x 10⁴ eV
C) E = 3.73 x 10⁹ eV
Explanation:
A)
For photon energy is given as:
where,
E = energy of photon = ?
h = 6.625 x 10⁻³⁴ J.s
λ = wavelength = 0.25 nm = 0.25 x 10⁻⁹ m
Therefore,
<u>E = 4.96 x 10³ eV</u>
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B)
The energy of a particle at rest is given as:
where,
E = Energy of electron = ?
m₀ = rest mass of electron = 9.1 x 10⁻³¹ kg
c = speed of light = 3 x 10⁸ m/s
Therefore,
<u>E = 4.19 x 10⁴ eV</u>
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C)
The energy of a particle at rest is given as:
where,
E = Energy of alpha particle = ?
m₀ = rest mass of alpha particle = 6.64 x 10⁻²⁷ kg
c = speed of light = 3 x 10⁸ m/s
Therefore,
<u>E = 3.73 x 10⁹ eV</u>