All categories

3 years ago

What is the answer to 3x+2-x=11x-9

2 answers:

8 0

3x+2−x=11x−9
Step 1: Simplify both sides of the equation.
3x+2−x=11x−93x+2+−x=11x+−9(3x+−)(2)=11x−9
(Combine Like Terms)
2x+2=11x−92x+2=11x−9

Step 2: Subtract 11x from both sides.
2x+2−11x=11x−9−11x−9x+2=−9

Step 3: Subtract 2 from both sides.
−9x+2−2=−9−2−9x=−11

Step 4: Divide both sides by -9.
−9x−9=−11−9x=119
ANSWER: 11/9

Hope it helps

Scilla [17]3 years ago

5 0

1.22222222 (1.2 repeated)

You might be interested in

The Lars family has a moisture farm on the planet Tatooine. They owned 5 acres of land. They sold 2/7 of their land to the Tuske

jeka57 [31]

Answer:

25/7 acres or 3 4/7 acres

Step-by-step explanation:

The sold 2/7 of the land.

1 - 2/7 = 7/7 - 2/7 = 5/7

They have 5/7 of the land left.

5/7 of 5 acres = 5/7 × 5 acres = 25/7 acres = 3 4/7 acres

7 0

2 years ago

Which of the following best describes the volume of a cylinder?

lord [1]

Option B : The area of the circular base multiplied by the height of the cylinder

3 0

3 years ago

identify an equation in the point-slope form for the line parallel to y=1/2 x -7 that passes through (-3,-2)

Mariulka [41]

Answer:

Step-by-step explanation:

hello :

note :

Use the point-slope formula.

y - y_1 = m(x - x_1) when : x_1= -3 y_1= -2 m= 1/2(parallel means same slope)

an equation in the point-slope form is : y +2 = 1/2(x+3)

3 0

3 years ago

Mr. Herrera is going to

Mnenie [13.5K]

Answer:

Mr. Herrera will hike 78 miles on 6th day.

Step-by-step explanation:

Given:

Number of miles Mr. Herrera will hike in 9 days = 117 miles

Total Number of days =9 days

Let us first find the number of miles he will hike in 1 day

By Using Unitary method we get,

Number of miles Mr. Herrera will hike in 1 days= $\frac{117} {9}=13\ miles$

We need to find miles hiked in 6th day.

Number of miles Mr. Herrera will hike on 6th day= Number of miles Mr. Herrera will hike in 1 days $\times$ Number of days = $13 \times 6 =78$

7 0

3 years ago

Find the dimensions of an open rectangular box with a square base that holds 2000 cubic cm and is constructed with the least bui

Vesnalui [34]

<h3>The dimensions of the given rectangular box are:</h3><h3>L = 15.874 cm , B = 15.874 cm , H = 7.8937 cm</h3>

Step-by-step explanation:

Let us assume that the dimension of the square base = S x S

Let us assume the height of the rectangular base = H

So, the total area of the open rectangular box

= Area of the base + 4 x ( Area of the adjacent faces)

= S x S + 4 ( S x H) = S² + 4 SH ..... (1)

Also, Area of the box = S x S x H = S²H

⇒ S²H = 2000

$\implies H = \frac{2000}{S^2}$

Substituting the value of H in (1), we get:

$A = S^2 + 4 SH = S^2 + 4 S(\frac{2000}{S^2}) = S^2 + (\frac{8000}{S})\\\implies A = S^2 + (\frac{8000}{S})$

Now, to minimize the area put :

$(\frac{dA}{dS} ) = 0 \implies 2S - \frac{8000}{S^2} = 0\\\implies S^3 = 4000\\\implies S = 15.874 \approx 16 cm$

Putting the value of S = 15.874 cm in the value of H , we get:

$\implies H = \frac{2000}{S^2} = \frac{2000}{(15.874)^2} = 7.8937 cm$

Hence, the dimensions of the given rectangular box are:

L = 15.874 cm

B = 15.874 cm

H = 7.8937 cm

3 0

3 years ago