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Roman55 [17]
3 years ago
14

Why does Napatha have a lower boiling point than disel?

Chemistry
1 answer:
Nostrana [21]3 years ago
3 0
Boiling points are related to the type of intermolecular forces between the compounds. if napatha has a lower boiling point hen it must have weaker bonds in it. Stronger bonds equal higher boiling points
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Need help on this question asap pleasee I would really appreciate it
Elza [17]

Answer:

See Explanation

Explanation:

An endothermic reaction is one in which energy is absorbed and the change in enthalpy for the reaction is positive.

If we look at the reaction 2HgO + 45kcal ----> 2Hg + O2; we will notice that

i) 45kcal of energy was taken in (absorbed) for the reaction to occur

ii) The value of the reaction enthalpy is positive

For these two reasons, the reaction is an endothermic reaction as written.

6 0
3 years ago
Equal amounts of N2 and O2 are added, under certain conditions, to a closed container. Which changes occur in the reverse reacti
geniusboy [140]
1) The forward reaction is N2 (g) + O2 (g)  → 2NO

(that reaction requires special contitions because at normal pressures and temperatures N2 and O2 do not react to form another compound.

2) The equiblibrium equation is

  N2 (g) + O2 (g)  ⇄ 2NO

3) Then, the reverse reaction is

2NO → N2(g) + O2(g)

Answer: 2NO → N2(g) + O2(g)
4 0
3 years ago
A ______ in medicine is a form of scientific argumentation in which evidence is used to rule out claims and support the best con
Gekata [30.6K]

Answer: Scientific reasoning

Explanation:

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3 years ago
Please help. Thank you!
scoray [572]

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Explanation:

6 0
3 years ago
Read 2 more answers
The enthalpy of fusion of solid n-butane is 4.66 kJ/mol. Calculate the energy required to melt 58.3 g of solid n-butane.
adelina 88 [10]

Answer : The energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

Explanation :

First we have to calculate the moles of n-butane.

\text{Moles of n-butane}=\frac{\text{Mass of n-butane}}{\text{Molar mass of n-butane}}

Given:

Molar mass of n-butane = 58.12 g/mole

Mass of n-butane = 58.3 g

Now put all the given values in the above expression, we get:

\text{Moles of n-butane}=\frac{58.3g}{58.12g/mol}=1.00mol

Now we have to calculate the energy required.

Q=\frac{\Delta H}{n}

where,

Q = energy required

\Delta H = enthalpy of fusion of solid n-butane = 4.66 kJ/mol

n = moles = 1.00 mol

Now put all the given values in the above expression, we get:

Q=\frac{4.66kJ/mol}{1.00mol}=4.66kJ

Thus, the energy required to melt 58.3 g of solid n-butane is, 4.66 kJ

7 0
3 years ago
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