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Goryan [66]
3 years ago
9

If an atom has 7 valence electrons, what will its charge be when it becomes an ion?

Chemistry
1 answer:
murzikaleks [220]3 years ago
4 0

Answer:

Well, he needs to take one more electron to have a stable structure. And by doing that the atom will have more electrons than protons and will turn into a negative ion.

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Lana balanced an equation so that the result was 2C2H3Br + 5O2 → 4CO2 + 2H2O + 2HBr. Which most likely represents the starting e
seropon [69]

Answer:

C2H3Br + O2 → CO2 + H2O + HBr

Explanation:

The term balancing of chemical reaction equation has a unique meaning in chemistry. What it actually means is to ensure that the number of atoms of each element on the left hand side of reaction equation becomes equal to the number of atoms of the same element on the right hand side of the reaction equation.

When we look at the equation; C2H3Br + O2 → CO2 + H2O + HBr, the number of atoms of each element on the left and right hand sides of the given equation are not the same hence the equation is unbalanced.

If we look at the equation; 2C2H3Br + 5O2 → 4CO2 + 2H2O + 2HBr, the number of atoms of each element on both sides of the reaction equation are now equal, thus the later equation is the balanced version of the former.

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3 years ago
For which of these does mRNA copy and carry the code?
Sphinxa [80]
The answer is D. Proteins. I know because I tried C. and I got it wrong. It was my last attempt on the quiz, and since I got it wrong they showed me the answer. (i like ur prp btw) 
5 0
3 years ago
Read 2 more answers
Find the volume of 56.0 grams of O2
N76 [4]

Answer:

39.2 L at STP

Explanation:

Convert the grams to moles first by dividing 56.0 by the molar mass of O2 (32.0) then convert to volume by multiplying by 22.4.

= 39.2 L

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3 years ago
Calculate the oxidation numbers of the elements in this equation<br> 2 Al2O3 → 4 Al + 3 O2
riadik2000 [5.3K]

Explanation:

Answer

Open in answr app

The rule used here is that the algebraic sum of the oxidation numbers of all the atoms a molecule is zero.

Al2O32× ( oxidation number of Al)+3× ( Oxidation number of O )  = 0

2× ( Oxidation number of Al) +3(−2)=0

2× ( oxidation number of Al) +6

∴ Oxidation number of Al =+3

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3 years ago
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Katarina [22]

Answer:

I think it is A _ B_C_D

Explanation:

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3 years ago
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