Answer:
12/13 kg, 18/13 kg
Explanation:
Let the masses are m and m'.
acceleration, a = 3.2 m/s^2
Force, F = 30 N
Tension, T = 18 N
By the diagram, using Newton's second law
F - T - m'g = m' a .... (1)
T - mg = ma ..... (2)
Substitute the values of F, T and a in equation (1) and equation (2)
30 - 18 = m' (9.8 + 3.2)
12 = 13 m'
m' = 12/ 13 kg
And, 18 = m (9.8 + 3.2)
m = 18/13 kg
Solution :
The conditions for the maximum in the Young's experiment is :
d sin θ = m λ, where m = 0, 1, 2, 3, .....
The angle between the central maximum and the 1st order maximum can be determined by setting the m = 1. So,
d sin θ = λ
Given : d = 100 λ
= 0.01 rad
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Answer: 13.2 seconds.
Explanation: using equation of motion; S= ut +1/2at² where u = initial velocity=0
S= distance travelled
a = acceleration due gravity
t= time.
1 foot = 0.305m so,
S= 2860 feet =872.3m
S= ut+1/2 at²
872.3 = 0×t + 1/2×10 × t²
872.3 =0 + 5t²
T²= 872.3/5
T²= 174.46
Take the square root of T we then have;
t = 13.2 seconds to one decimal place.