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Anna35 [415]
2 years ago
10

I'll give you a BRAINLIEST if you help me with these questions and they have to be correct.

Physics
1 answer:
irina1246 [14]2 years ago
7 0
2. 3 I think I’m not sure
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If a truck loses 5610 J of energy as it slows down due to an external force of 425 N, what distance will it have moved after the
lara31 [8.8K]

Answer:

13.2m

Explanation:

Step one:

given data

Energy= 5610J

Force F= 425N

Required

The distance traveled

Step two:

We know that work done is given as

WD= force* distance

so

5610=425*d

divide both sides by 425

d= 5610/425

d=13.2m

3 0
3 years ago
A centrifuge rotor (hollow disk) is rotating at 10,000 rpm is shut off and brought to rest by a constant frictional torque of 1.
Y_Kistochka [10]

Answer:

The no of revolutions rotor turn before coming to rest is 1,601.1943 and time taken is equal to 19.21 seconds

Explanation:

here we know that torque = I×α

     α= angular acceleration

     I = moment of inertia of hollow disc = m×k^{2}

  given that m=4.37kg

                    k=0.0710m

           torque=1.2Nm

        w_{o}=10000\times \frac{\pi}{30} rad /s

         \alpha =\frac{torque}{I}

from the above equation we can calculate the angular acceleration of the hollow disc .

  since  w^{2}-w_o^{2} =2\alpha\theta

 from this above equation  \theta=\frac{w^{2}-w_{o}^{2}}{2\alpha }

   no of revolutions = \frac{\theta}{2\pi}  = 1,601.1943.

Now to calculate time we know that time = \frac{2\theta}{w+w_{o}}

   so upon calculating we will be getting t=19.21 seconds

5 0
3 years ago
The energy released from condensation in thunderstorms can be very large. Calculate the energy (in J) released into the atmosphe
makkiz [27]

Answer:

7.19 * 10^14J

Explanation:

Given that

Density of water Pwater= 1000kg/m3

R=2.1km = 2.1*10^3m

H= 2.3cm. = 2.3*10^-2m

Lv water= 2256 * 10^3J/kg

First, mass of water need to be calculated, using an imaginary cylinder

Density= Mass /Volume

Mass= Density* Volume

Volume of a cylinder= πR2h

Therefore mass= PπR2H

= 1000 * π * (2.1 *10^3)^2 * (2.3 * 10^-2)

= 3.18 *10^8

Heat Released Qv = mLV

= 3.18*10^8 * 2236*10^3

= 7.19 * 10^14J

7 0
3 years ago
Read 2 more answers
You are performing an experiment that requires the highest possible energy density in the interior of a very long solenoid. Whic
Alinara [238K]

Answer:

b. increasing the number of turns per unit length on the solenoid

e. increasing the current in the solenoid

Explanation:

As we know that energy density depends on the strength of the magnetic field. The magnetic field strength depends on the no of turns of the solenoid and the current passing through it. The greater the number of turns per unit length, greater the current passing through it, more stronger the magnetic field is. As

B = μ₀nI

n = no of turns

I = current through the wire

So the right options are

b. increasing the number of turns per unit length on the solenoid

e. increasing the current in the solenoid

5 0
3 years ago
The impact of the type of material of which the slope is made on acceleration
Pachacha [2.7K]

 The impact of the material type with which the slope is made affects the acceleration. Acceleration will be higher and smoother if the material of the slope surface is smoother as opposed to a texture which is not smooth. Smoother surface allows more acceleration because it will have less friction and resistance. Otherwise the friction will slow the object down for example a grassy ground will have more friction than a well maintained marble floor. 

6 0
3 years ago
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