Well let see, we don't have any information about the initial distance we have to use our logic
assuming that the distance moves from 1 to 2 m with initial speed , it means that the distance factor is 2
Since the initial speed has doubled, it would be very likely that the factor of the distance is MORE THAN 2 . Find the answer that either got 3 or 4 distance factor
hope this helps
Answer:
The balls cross paths above 1/2h
Explanation:
Let's analyze the picture when the first ball is at the top of its flight and the second ball starts to flight.
When the second ball is thrown it has the maximum speed and the first ball starts with an initial velocity equal to zero. We know that they will cross at the same time, hence the second ball will travel a longer distance, due to its velocity, than the first ball.
Therefore, the correct answer is above the midpoint of h (1/2h).
I hope it helps you!
Protista, fungi, plantae and animalia
Answer:
Diaplacement s=1.80km
Final velocity v=360km/h
It starts from rest. So, initial velocity u=0
We need to find the constant acceleration (a).
using the equation of motion v
2
=u
2
+2as
360
2
=0
2
+2×a×1.8
a=
3.6
360×360
a=36000km/h
2