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2 years ago

A bullet with a mass of 0.1 kg is travelling at

Physics

1 answer:

mel-nik [20]2 years ago

6 0

The block with the bullet lodged in the block is now travelling at 2.133 m/s.

<h3>What is momentum conservation principle?</h3>

When there is no external force acting on the system, the momentum remains conserved.

For inelastic collision, after collision both objects travel with common speed.

m1u1 + m2u2 =(m1 +m2)v

Substitute initial velocity of bullet u1 =320 m/s , initial velocity of block u2 =0, mass of bullet m1 = 0.1 kg and mass of block m2 = 14.9 kg.

Solve for the final velocity of bullet,

0.1 x 320 + 14.9 x 0 = (0.1 +14.9) x v

v = 2.133 m/s

Thus, the block with the bullet lodged in block now travelling at 2.133 m/s.

Learn more about momentum conservation principle.

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