Answer:
(a) the input force is 36.56 N
(b) the input force is 37.49 N
Explanation:
Given;
density of hydraulic oil, ρ = 8.53 x 10² kg/m³
radius of plunger, r₁ = 0.135 m
radius of piston, r₂ = 5.43 x 10⁻³ m
Part (a) The input force needed to support 22600-N weight, when the bottom surfaces of the piston and plunger are at the same level;
Where;
P is pressure
F is force
A is circular area = πr²
Part (b) The input force needed to support 22600-N weight, when the bottom surface of the output plunger is 1.20 m above that of the input plunger
But, F = PA and A = πr²
Inertia. It also is the tendency of an object in motion to stay in motion in one specific direction.
The work done by the man pushing the car over the given distance is 1000J.
Given the data in the question;
- Mass of car;
- Acceleration of the car;
- Distance covered by the car;
Work done; 
<h3>Work done</h3>
Work done is simply defined as the energy transfer that takes place when an object is either pushed or pulled over a certain distance by an external force. It is expressed as;
Where f is force applied and d is distance travelled.
To determine the work done by the man, we first solve for the force applied F.
From Newton's Second Law; 
We substitute our given values into the expression
Next we substitute our values into the expression of work done above.
Therefore, the work done by the man pushing the car over the given distance is 1000J.
Learn more about work done: brainly.com/question/26115962
Power = (energy) divided by (time)
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