Answer:g(x)=(1/5x)^2
Step-by-step explanation: A P E X
Answer:
The minimum value of a function is the lowest point of a vertex. If your quadratic equation has a positive a term, it will also have a minimum value. ... If you have the equation in the form of y = ax^2 + bx + c, then you can find the minimum value using the equation min = c - b^2/4a.
Answer:
1) 19.6
2) 144
3) 0.486
4) 56.4
5) 90.2
6) 54
7) 1.19
8) 121
9) 2.86
10) 0.9
Step-by-step explanation:
I FOUND YOUR COMPLETE QUESTION IN OTHER SOURCES.
SEE ATTACHED IMAGE.
Part A:
The differential equation is:
y '= 0.08y
The initial condition is:
P (0) = 500 Part B:
The formula for this case is:
P (t) = 500exp (0.08 * t) Part C:
After five days we have to evaluate t = 5 in the equation.
We have then:
P (5) = 500 * exp (0.08 * 5)
P (5) = 745.9123488
Rounding:
P (5) = 746
Answer:
22 ft²
Step-by-step explanation:
he needs 2 sides that are 2 x 3 feet
2 sides that are 3 x 1 and 2 sides that are 2 x 1
add these up to get 22 ft