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Elan Coil [88]
3 years ago
13

Nethan made 8 rose bouquets and 6 daffodil bouquets. Nethan only has enough flowers to make at most 20 rose or daffodil bouquets

total. Let x represent the number of more rose bouquets and y represent the number of more daffodil bouquets that Nethan can make. Show the relationship between x and y graphically.

Mathematics
1 answer:
Solnce55 [7]3 years ago
3 0

Answer:

Nethan made 8 rose bouquets and 6 daffodil bouquets.

Nethan only has enough flowers to make at most 20 rose or daffodil bouquets total.

Let x represents the number of more rose bouquets.

Let y represents the number of more daffodil bouquets.

The maximum bouquets that can be made = 20

And the number of bouquets made are = 14

So, additional bouquets are = 20-14=6

In equation form we can show like :

x +y= 6

or y=6 -x

or x=6- y

Putting values of x as 0,2,4 and 6 we get:

When x = 0 then y = 6  

When x = 2 then y = 4

When x = 4 then y = 2

When x = 6 then y = 0

You can see the graph attached.

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A system of linear inequalities is shown below.
Helga [31]
A) Isolate y in both inequalities

1) x + y ≥ 4 => y ≥ 4 - x
2) y < 2x - 3

B) Draw the lines for the following equalities:

1) y = 4 - x
2) y = 2x - 3

C) Shade the regions of solutions

1) The region that is over the line y = 4 - x
2) The region that is below the line y = 2x - 3

The solution is the intersection of both regions; this is the sector between both lines that is to the right of the intersection point, including the portion of the very line y = 4 - x and excluding the portion of the very line y = 2x - 3


5 0
3 years ago
Patrick raced round a 440 metre circular track and stopped suddenly after 900 metres . How far was she from the starting point a
castortr0y [4]

Answer:

20 meters

Step-by-step explanation:

The track is circular so it means that after Patrick raced the entire track he is back at the starting point. In other words, every 440 meters he is back to the beginning.

So we would have that, if he races round the track twice, he would run 440(2) = 880 meters and he would be back at the starting point.

The problem asks us how far is he from the starting point at the 900 meter mark. If at 880 meters he is at the starting point, then at 900 meters he would be 900-880=20 meters from the starting point.

8 0
3 years ago
1.2 x 10^19 x 5.88 x 10^12
Lapatulllka [165]

9514 1404 393

Answer:

  7.056 × 10^31

Step-by-step explanation:

The applicable rule of exponents is ...

  (10^a)(10^b) = 10^(a+b)

__

  (1.2\times10^{19})\times(5.88\times10^{12})=(1.2\cdot5.88)\times10^{19+12}\\\\=\boxed{7.056\times10^{31}}

As you know, the commutative and associative properties of multiplication let you rearrange the order of the product to any convenient form. Here it is convenient to group the mantissas together and the powers of 10 together.

__

<em>Additional comments</em>

This is a product your scientific or graphing calculator can produce for you. Likely it will display the result in scientific notation because it won't have enough display digits to show you the product any other way. For smaller numbers, you can set the display mode to give you scientific notation.

If you choose to use a spreadsheet to perform this calculation, the numbers would be entered as 1.2e19 and 5.88e12. The result will be something like 7.056e31. You may have to format the display to show 3 decimal places.

7 0
2 years ago
The additive inverse of 10 is -17. If 10 + (-17) = 0, then the numbers are additive inverses. True or False?
Vesnalui [34]

Answer:

False

Do not worry I am not giving you any false answers

3 0
2 years ago
Please help!
Ainat [17]
<span>(x – h)^2 + (y – k)^2 = r<span>^2


this equation is a derivative of the equation of a circle

x^2 + y^2 = r^2
This is from the origin. If we move the in x or y then the radius will change positions in x or y


with h = -3 and k = 1

we can plug in each set of numbers and solve.

we find Z to be on the circle edge!</span></span>
8 0
3 years ago
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