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3 years ago

Write the equation for the Pythagorean Theorem and indicate which letter is the hypotenuse. ill mark you brailiest.

Mathematics

1 answer:

love history [14]3 years ago

8 0

A^2 +b^2 =c^2
c^2 will be your hypotenuse
Hope that helps

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Lianna is buying 10 apples for $6.50. What is the unit price per apple?

Snezhnost [94]

Given :-  $\sf Lianna\: buys \:10 \:apples\: for \:\$ 6.50 .$

To Find :-  $\sf The\: unit \:price \:of \:each\: Apple .$

Answer :- Its given that cost of 10 apples is $6.50 .

So, by Unitary method , we can solve this ,

→ Cost of 10 apples is $ 6.50.

→ Cost of 1 apple will be $\sf \dfrac{\$6.50}{10}$

= $\red{\bf \$0.65}$

Hence the required answer is $0.65.

6 0

3 years ago

The value of y varies directly with x. If x = 6, then y = 27. What is the value of y when x = 10 ?

Alik [6]

B - 45 because 27 divided by 6 is 4.5 and then 10x4.5=44

7 0

3 years ago

15. Write an equation of a line in standard form that: 2x + 5 passes through the point (1, 5) and is parallel to y=2x+5

lesya [120]

Answer:

$y = 2x +3$

Step-by-step explanation:

Given

Parallel: $y = 2x + 5$

Passes through (1,5)

Required

Determine the equation

Because it is a parallel to $y = 2x + 5$ then they have the slope.

The slope of $y = 2x + 5$ is 2 i.e. from $y = mx + b$

So:

$m = 2$

The line equation is then calculated using:

$y = m(x - x_1) + y_1$

$y = 2(x - 1) + 5$

$y = 2x - 2 + 5$

$y = 2x +3$

5 0

3 years ago

A triangle has sides with lengths of 28 millimeters, 34 millimeters, and 43 millimeters. Is it a right triangle?

dezoksy [38]

To find if it's a right triangle, we use the Pythagorean Theorem of a² + b² = c² where a and b are the legs of the triangle (the shorter measurements) and c is the hypotenuse (the biggest measurement).

28² + 34² = 43²
784 + 1156 = 1849
1940 ≠ 1849

No. This is not a right triangle. The sum of the squares of the shorter measurements (AKA the legs) do not equal the square of the biggest measurement.

6 0

4 years ago

HELP PLEASE THIS IS REALLY IMPORTANT

Vikentia [17]

Distance formula:
$d= \sqrt{(x_b-x_a)^2+(y_b-y_a)^2} 
\\
d=3 \ \ x_a= 4 \ \ y_a=2 \\ \\ \boxed{ 3= \sqrt{(x-4)^2+(y-2)^2} }$

5 0

4 years ago