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Umnica [9.8K]
2 years ago
11

Write the equation for the Pythagorean Theorem and indicate which letter is the hypotenuse. ill mark you brailiest.

Mathematics
1 answer:
love history [14]2 years ago
8 0
A^2 +b^2 =c^2
c^2 will be your hypotenuse
Hope that helps
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509-458 = 49. hope this helps :)
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HELP PLEASE WILL MARL BRANIEST IF right
Kaylis [27]

Answer:

A bit of a doosy, but bare with me: f*g*h(x) = x^2+54x-12x\sqrt{x} -108\sqrt{x} +90

Step-by-step explanation:

So explaining this is a bit awkward as well, but I can try...So

Starting from g(x) working that backwards into f(x), so...

g(x) = x-3

f(x) = (x^4+9)

Take your g(x) and plug it into your f(x) into every x you see

f(g(x)) = (x-3)^4+9 ~ I hope you can visualize this, but do you see how g(x) plugs into f(x)...

Now you still have one more step which you still need to include h(x), so

Remember h(x) = \sqrt{x}

Now plug in your h(x) into every x you see from f(g(x)) and it should look like...

(\sqrt{x} -3)^4 + 9

3 0
3 years ago
What is the distance between the center of the circle with equation $x^2+y^2=6x-8y+24$ and the point $(-3,-12)$?
kvasek [131]

Answer:

The answer to your question is: 10 units

Step-by-step explanation:

P (-3, -12)

1.- Find the center of the circle

                               x² + y² = 6x - 8y + 24

                              x² - 6x + (   )²  + y² + 8y + (  )²  = 24

                              x² - 6x + (3)² + y² + 8y + (4)² = 24 + 9 + 16

                              (x - 3)² + (y + 4)² = 49

                              Center (3, -4)

2.- Find the distance between the center and the point given

Formula

d = \sqrt{(x2- x1)^{2} + (y2 - y1)^{2} }

Substitution

d = \sqrt{(-3 - 3)^{2} + (-12 +4)^{2} }

d = \sqrt{(-6)^{2} + (-8)^{2} }

d = \sqrt{36 + 64} }

d = \sqrt{100}

d = 10 units

             

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3 years ago
Find the product of 2x^4(3x^2 + 4x + 1)
lozanna [386]

Answer:

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<h3><u>6x⁶+8x⁵+2x⁴</u> is the right answer.</h3>
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