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Umnica [9.8K]
2 years ago
11

Write the equation for the Pythagorean Theorem and indicate which letter is the hypotenuse. ill mark you brailiest.

Mathematics
1 answer:
love history [14]2 years ago
8 0
A^2 +b^2 =c^2
c^2 will be your hypotenuse
Hope that helps
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How would you write 2x^2-7=11 in both quadratic property and square root property?
dangina [55]

Answer:

Quadratic Property 2x^2-18=0

Square Root Property x=√9 or x=+3 or x=-3

Step-by-step explanation:

Quadratic Property or a quadratic Function is of the form ax^2+bx+c=0. So our task is to equate the given expression to zero. We can equate the expression to zero by subtracting 11 on both the sides. In doing so, we get 2x^2-18=0. This is the quadratic Property of the given Expression.

Square property is finding the value for x. we have make x equal to some value. Since we already have the quadratic Property as 2x^2-18=0, we can use this to find the value of x.

so, 2x^2=18

or x^2=18/2=9

or x=√9= +3 or -3.

6 0
3 years ago
4(x+2)=30 <br> I need help
mars1129 [50]

Answer:

x = 11/2

Step-by-step explanation:

8 0
3 years ago
F(x) = x2 what is g(x)?
Naily [24]

Answer:

i got the same problem

Step-by-step explanation:

3 0
2 years ago
Find the missing side lengths.
USPshnik [31]
Answer: A, because it is a 30, 60, 90 triangle. To get the 34 they had to times the number by 2 so you divide that by 2 and it gives you 17 then you have the square root of 3* 17, that doesn’t mathematically work so it stays as 17*the square root of 3
6 0
3 years ago
4. What is the circumference of a circle whose area is 81π cm squared?
vichka [17]
Area = pi*r^2
Circumference = 2pi*r

Step 1: find the radius from area
81pi=pi*r^2
81=r^2
9=r

Step 2: plug in radius to the circumference equation

Circumference = 2pi*r

18pi is the answer, otherwise know as 56.52 as well.
7 0
3 years ago
Read 2 more answers
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